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a, Cl2 + 2Na -> (t°) 2NaCl
2NaCl + H2SO4 -> Na2SO4 + 2HCl
4HCl + MnO2 -> MnCl2 + 2H2O + Cl2
Ca + Cl2 -> (t°) CaCl2
b, 4HCl + MnO2 -> MnCl2 + 2H2O + Cl2
2Fe + 3Cl2 -> (t°) 2FeCl3
FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl
2NaCl + H2SO4 -> Na2SO4 + 2HCl
c, MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2
3Cl2 + 6KOH (đặc nóng) -> 5KCl + KClO3 + 3H2O
2KCl + H2SO4 -> K2SO4 + 2HCl
4HCl + MnO2 -> MnCl2 + 2H2O + Cl2
2Cl2 + 2Ca(OH)2 -> CaCl2 + Ca(OCl)2 + 2H2O
d, 16HCl + 2KMnO4 -> 5Cl2 + 8H2O + 2KCl + 2MnCl2
3Cl2 + 6KOH (đặc nóng) -> 5KCl + KClO3 + 3H2O
2KCl -> (đpnc) 2K + Cl2
Cl2 + 2NaBr -> 2NaCl + Br2
Br2 + 2NaI -> 2NaBr + I2
a. MnO2 +4HCl→Cl2+2H2O+MnCl2
2Fe+3Cl2→2FeCl3
FeCl3+3NaOH → Fe(OH)3 +3NaCl
Fe(OH)3+3NaCl→ FeCl3 +3NaOH
FeCl3+3AgNO3→3AgCl+Fe(NO3)3
2AgCl→Cl2+2Ag
b. 2KMnO4 +16HCl→ 5Cl2+8H2O+2KCl+2MnCl2
Cl2+H2→2HCl
CuO+2HCl→CuCl2+H2O
CuCl2+Ba(OH)2→ BaCl2+Cu(OH)2
BaCl2+H2SO4→ BaSO4.+2HCl
c.2 NaCl+H2SO4→ 2HCl +Na2SO4
2HCl→ Cl2 +H2
3Cl2+2Fe→ 2FeCl3
FeCl3+3NaOH →3NaCl +Fe(OH)3
2NaCl+2H2O→2NaOH+Cl2+H2
NaOH+HCl→NaCl+H2O
2NaCl→Cl2+2Na
Cl2+Ca →CaCl2
CaCl2+2AgNO3→2AgCl +Ca(NO3)2
2AgCl→2Ag+Cl2
Đáp án A
Có 2 chất trong dãy chỉ chứa liên kết cộng hóa trị không cực là N2, H2
a/
\(2HCl\underrightarrow{^{đpdd}}H_2+Cl_2\)
\(3Cl_2+2Fe\underrightarrow{^{to}}2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\)
\(2NaCl+H_2SO_4\underrightarrow{^{to}}Na_2SO_4+2HCl\)
\(HCl+CuO\rightarrow CuCl_2+H_2O\)
\(CuCl_2+AgNO_3\rightarrow AgCl+Cu\left(NO_3\right)2\)
b/
\(2HCl\underrightarrow{^{đpdd}}H_2+Cl_2\)
\(Cl_2+2Na\underrightarrow{^{to}}2NaCl\)
\(2NaCl+H_2SO_{4_{dac}}\underrightarrow{^{to}}Na_2SO_4+2HCl\)
\(2HCl+Fe\rightarrow FeCl_2+H_2\)
c/
\(MnO_2+4HCl_đ\underrightarrow{^{to}}MnO_2+Cl_2+2H_2O\)
\(Cl_2+2K\underrightarrow{^{to}}2KCl\)
\(2KCl+H_2SO_4\underrightarrow{^{to}}K_2SO_4+2HCl\)
\(2HCl\underrightarrow{^{đpdd}}H_2+Cl_2\)
\(Cl_2+2NaBr\rightarrow2NaCl+Br_2\)
\(Br_2+2NaI\rightarrow NaBr+I_2\)
d/
\(2KMnO_4+16HCl_đ\underrightarrow{^{to}}2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(Cl_2+H_2\underrightarrow{^{as}}2HCl\)
\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
\(FeCl_3+3AgNO_3\rightarrow3AgCl+Fe\left(NO_3\right)_3\)
a)
\(4HCl+MnO_2\rightarrow MnCl_2+Cl_2+2H_2O\\ 3Cl_2+2Fe\xrightarrow[]{t^o}2FeCl_3\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ 2NaCl+H_2SO_{4\left(\text{đ}\right)}\xrightarrow[]{t^o}Na_2SO_4+2HCl\)
b)
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\\ Cl_2+H_2\xrightarrow[]{a/s}2HCl\\ 6HCl+Fe_2O_3\rightarrow2FeCl_3+3H_2O\\ FeCl_3+3AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\)
c)
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\\ Cl_2+H_2\xrightarrow[]{a/s}2HCl\\ 2HCl+Fe\rightarrow FeCl_2+H_2\\ FeCl_2+2AgNO_3\rightarrow Fe\left(NO_3\right)_2+2AgCl\)
d)
\(3Cl_2+6KOH_{\left(\text{đ}\text{ặ}c\right)}\xrightarrow[]{t^o}5KCl+KClO_3+3H_2O\\ 2KClO_3\xrightarrow[MnO_2]{t^o}2KCl+3O_2\\ 2KCl\xrightarrow[]{\text{đ}pnc}2K+Cl_2\\ Cl_2+Ca\xrightarrow[]{t^o}CaCl_2\)
e)
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\\ 3Cl_2+6KOH_{\left(\text{đ}\text{ặ}c\right)}\xrightarrow[]{t^o}5KCl+KClO_3+3H_2O\\ 2KClO_3\xrightarrow[MnO_2]{t^o}2KCl+3O_2\\ 2KCl\xrightarrow[]{\text{đ}pnc}2K+Cl_2\)
g)
\(2KI+O_3+H_2O\rightarrow2KOH+I_2+O_2\\ I_2+H_2\xrightarrow[]{t^o,p,xt}2HI\\ 2HI+Cl_2\rightarrow2HCl+I_2\\ KOH+HCl\rightarrow KCl+H_2O\)
Em comment thêm 1 cái nhé, câu trả lời được 2GP á.
Đáp án đúng : C