Question

[Vũ Mạnh Dũng]

CMR: 4ⁿ⁺³ + 4ⁿ⁺² - 4ⁿ⁺¹ - 4ⁿ chia hết cho 300

Answer 1

[Phạm Nguyễn Tất Đạt]

Đặt A=\(4^{n+3}+4^{n+2}-4^{n+1}-4^n\)

A=\(4^{n-1}\left(4^4+4^3-4^2-4\right)\)

A=\(4^{n-1}\cdot300⋮300\)

Answer 2

[Nguyễn Huy Tú]

Ta có:

\(4^{n+3}+4^{n+2}-4^{n+1}-4^n\)

\(=4^{n-1}.4^4+4^{n-1}.4^3-4^{n-1}.4^2-4^{n-1}.4\)

\(=4^{n-1}.\left(4^4+4^3-4^2-4\right)\)

\(=4^{n-1}.300⋮300\)

\(\Rightarrow4^{n+3}+4^{n+2}-4^{n+1}-4^n⋮300\left(đpm\right)\)