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![](https://rs.olm.vn/images/avt/0.png?1311)
2) 2KMnO4 + 16HCl = 2KCl + 2MnCl2 + 5Cl2 + 8H2O
Cl2 + H2 = 2HCl ( điều kiện ánh sáng )
2HCl + Fe = FeCl2 + H2
FeCl2 + 2AgNO3 = 2AgCl + Fe(NO3)2
2AgCl = 2Ag + Cl2
![](https://rs.olm.vn/images/avt/0.png?1311)
Cl2 vừa có tính oxi hóa vừa có tính khử
Cl2(Cl0) → NaCl(Cl-1) + NaClO(Cl+1)
![](https://rs.olm.vn/images/avt/0.png?1311)
Chọn đáp án C
C l 2 + 2KOH → KCl (A) + KClO (B) + H 2 O
3 C l 2 + 6KOH → t o 5KCl (A) + K C l O 3 (C) + 3 H 2 O
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(H_2+Cl_2\underrightarrow{^{as}}2HCl\)
\(NaOH+HCl\rightarrow NaCl+H_2O\)
\(2NaCl\underrightarrow{^{đpnc}}2Na+Cl_2\)
\(4Cl_2+H_2S+4H_2O\rightarrow8HCl+H_2SO_4\)
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
2.
\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)
\(6KOH+3Cl_2\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(Fe+\frac{3}{2}Cl_2\underrightarrow{^{to}}FeCl_3\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)
\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+Cl_2+H_2\)
3.
\(BaCl_2\underrightarrow{^{đpnc}}Ba+Cl_2\)
\(Cl_2+H_2\underrightarrow{^{as}}2HCl\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(2FeCl_2+3Cl_2\rightarrow2FeCl_3\)
\(3Ba\left(OH\right)_2+2FeCl_3\rightarrow3BaCl_2+2Fe\left(OH\right)_3\)
\(BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)
4.
\(C_2H_2+Cl_2\rightarrow2C+2HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\)
\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+H_2+Cl_2\)
\(3Cl_2+6KOH\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
5.
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)
\(2Fe+3Cl_2\rightarrow2FeCl_3\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+AgNO_3\rightarrow Cu\left(NO_3\right)_2+2AgCl\)
6.
\(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)
\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+H_2O\)
\(6KOH+3Cl_2\rightarrow5KCl+KClO_3+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(2KCl\underrightarrow{^{đpnc}}2K+Cl_2\)
\(Cl_2+Ca\left(OH\right)_2\rightarrow CaOCl_2+H_2O\)
1. MnO2 +4HCl→ Cl2+MnCl2+4H2O
Cl2+2H2→ 2HCl
HCl+Na2O→ NaCl+H2O
2NaCl → Cl2+2Na
2Cl2+2H2O+CO2→ H2SO4 +4HCl
H2SO4+BaCl2→ 2HCl+BaSO4
2. 2KMnO4 +16HCl→ 5Cl2+8H2O+2KCl+2MnCl2
2Cl2+6KOH→ KClO3 +5KCl+3H2O
KClO3+6HCl→ 3Cl2+KCl+3H2O
3Cl2+2Fe→2 FeCl3
FeCl3+3KOH→ 3KCl +Fe(OH)3
2KCl+2H2O→ KOH+Cl2+2H2O
3. BaCl2 → Cl2+Ba
Cl2+2H2→ 2HCl
2HCl+Fe→ FeCl2+H2
2FeCl2+Cl2→ 2FeCl3
2FeCl3+3Ba(OH)2→ 3BaCl2+2Fe(OH)3
BaCl2+H2SO4→ 2HCl+BaSO4
Mỏi tay rồi :((
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(C_2H_2+Cl_2\rightarrow C+2HCl\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2KOH\rightarrow2KCl+Cu\left(OH\right)_2\)
\(2KCl+2H_2O\rightarrow2KOH+Cl_2+H_2\) ( đpcmn )
\(6KOH+3Cl_2\rightarrow KClO_3+5KCl+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
b, \(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\) ( NaCl khan , H2SO4 đặc nóng )
\(2HCl\rightarrow H_2+Cl_2\) ( Đpdd )
\(6KOH+3Cl_2\rightarrow KClO_3+5KCl+3H_2O\)
\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)
\(2KCl\rightarrow2K+Cl_2\) ( Đpdd )
\(Cl_2+Ca\left(OH\right)_2\rightarrow CaOCl_2+H_2O\)
Đáp án C
Cl2 + 2KOH → KCl + KClO + H2O
3Cl2 + 6KOH
5KCl + KClO3 + 3H2O