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B = 4^9.36+64^4
16^4.100
B = 2^20.(9+16)
2^18.5^2
B = 2^20.5^2
2^18.5^2
B = 2^2
B = 4
D = 4^6.3^4.9^5
6^12
D = 2^12.3^4.9^5
2^12.3^12
D = 2^12.3^14
2^12.3^12
D = 3^2
D = 9
\(\frac{4^9.36+64^4}{16^4.100}=\frac{4^{10}\left(9+8\right)}{4^{10}.25}=\frac{17}{25}\)
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a, =\(3^4+2^5=81+32=113\)
b, =\(3.\left(4^2-2.3\right)=3.\left(16-6\right)=3.10=30\)
c, =\(\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\dfrac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)
d, =\(\dfrac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}=3\)
e, =\(\dfrac{3^6.5^3.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}=\dfrac{3^{10}.2^{10}.5^7}{2^{10}.3^{10}.5^5}=5^2=25\)
g, =\(\dfrac{2^5.\left(2^8+1\right)}{2^2.\left(2^8+1\right)}=\dfrac{2^5}{2^2}=2^3=8\)
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\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{2^{12}.3^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)
\(\frac{4^6\cdot3^4\cdot9^5}{6^{12}}\)
\(=\frac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}\)
\(=\frac{1\cdot3^{14}}{1\cdot3^{12}}\)
\(=\frac{3^{14}}{3^{12}}\)
\(=3^2\)
\(=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(4096.81.729\right):2176782336\)
\(\left(331776.729\right):2176782336\)
\(\left(241864704\right):2176782336\)
\(\frac{4^6.3^4.9^3}{6^{12}}=\frac{2^{12}.3^4.3^6}{2^{12}.3^{12}}=\frac{2^{12}.3^{10}}{2^{12}.3^{12}}=\frac{1}{3^2}=\frac{1}{9}\)
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a, \(\dfrac{3^8}{3^4}+2^2.2^3\)
= 34 + 25
= 113
b, 3.42 - 2.32
= 3.(42 - 2.3)
= 3.(16 - 6)
= 3.10
= 30
c, \(\dfrac{4^6.3^4.9^5}{6^{12}}\)
= \(\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}\)
= \(\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}\)
= \(\dfrac{3^{14}}{3^{12}}\)
= 32
@Dương Tuyết Mai
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(C=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=3^{4+10-12}=3^2=9\)
Mk cảm ơn bn nhé. Mong bn giúp mk ở những bài tập tiếp theo