Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,2Al_2O_3\rightarrow\left(đpnc,criolit\right)4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\rightarrow\left(t^o\right)Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(b,2Cu+O_2\rightarrow\left(t^o\right)2CuO\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2+2KCl\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\)
\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 2AlCl_3+3BaSO_4\downarrow\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow +3NaCl\\ 2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{đpnc}4Al+3O_2\)
Dãy biến hóa 1: Al → AlCl3 → Al(OH)3 → Al2O3
Dãy biến hóa 2: AlCl3 → Al(OH)3 → Al2O3 → Al PTHH
dãy biến hóa 1: 1): 2Al + 6HCl → 2AlCl3 + 3H2
(2): AlCl3 + 3NaOH → Al(OH)3 + 3NaCl
(3): 2Al(OH)3 t0 → Al2O3 + 3H2O PTHH
dãy biến hóa 2:
(1): AlCl3 +3NaOH → Al(OH)3+ 3NaCl
(2): 2Al(OH)3 t0 → Al2O3 + 3H2O
(3): 2Al2O3 dpnc → 4Al + 3O2
\(4Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+6NaOH\rightarrow2Al\left(OH\right)_3+3Na_2SO_4\)
\(Al\left(OH\right)_3+3HCl\rightarrow AlCl_3+3H_2O\)
\(4Al+3O_2--^{t^o}->2Al_2O_3\)
\(Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3Cu\left(OH\right)_2--->2Al\left(OH\right)_3+3CuSO_4\)
\(Al\left(OH\right)_3+3HCl---->AlCl_3+3H_2O\)
\(2Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3\underrightarrow{^{^{t^o}}}Al_2O_3+3H_2O\)
\(2NaOH+Al_2O_3\rightarrow2NaAlO_2+H_2O\)
\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)
\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)
Al+H2SO4 -> Al2(SO4)3+ H2 \(\uparrow\)
Al2(SO4)3 +HCl -> AlCl3+ H2SO4
AlCl3 +Ca(OH)2 -> Al(OH)3 +CaCl2
Al(OH)3 - to> Al2O3 +H20
\(2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\)
\(1.\\ Al\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}Al_2\left(SO_4\right)_3\underrightarrow{\left(3\right)}AlCl_3\underrightarrow{\left(4\right)}Al\left(NO_3\right)_3\underrightarrow{\left(5\right)}Al\left(OH\right)_3\)
\(\left(1\right)2Al+\frac{3}{2}O_2\underrightarrow{t^o}Al_2O_3\\ \left(2\right)Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\\ \left(3\right)Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow BaSO_4+2AlCl_3\\ \left(4\right)AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ \left(5\right)Al\left(NO_3\right)_3+3NaOH\rightarrow3NaNO_3+Al\left(OH\right)_3\)
\(2.\)
\(n_{CaCO_3}=\frac{10}{100}=0,1\left(mol\right)\)
\(PTHH:CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)
(mol)____0,1________0,1________0,1_________
\(PTHH:MgCO_3+2HCl\rightarrow MgCl_2+H_2O+CO_2\)
(mol)______0,1_____________________________0,1__
\(m_{MgCO_3}=0,1.84=8,4\left(g\right)\)
\(m_{Cu}=64.\frac{0,315.10^{23}}{6.10^{23}}=3,36\left(g\right)\)
\(\%m_{Cu}=\frac{3,36}{3,36+8,4}.100\%=28,6\left(\%\right)\Rightarrow\%m_{MgCO_3}=100-28,6=71,4\left(\%\right)\)
1.
a. Al —> Al2O3 —> Al2(SO4)3 —>AlCl3 —> Al (OH)3 —> Al2 (SO4)3 —> Al(OH)3 —> Al2O3 —> Al
a) 2Al+3O2-->2Al2O3
Al2O3+3H2SO4--->Al2(SO4 )3+3H2O
Al2(SO4)3+3BaCl2-->2AlCl3+3BaSO4
AlCl3+3NaOH--->3NaCl+Al(OH)3
2Al(OH)3+3MgSO4---->Al2(SO4)3+3Mg(OH)2
Al2(SO4)3+ 6NaOH---->2Al(OH)3+3Na2SO4
2Al(OH)3---to-->AL2O3+3H2O