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![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{Mg}=\dfrac{3}{24}=0,125mol\)
\(n_{HCl}=\dfrac{10,95}{36,5}=0,3mol\)
\(Mg+2HCl\rightarrow MgCl_2+H_2\)
0,125 < 0,3 ( mol )
0,125 0,125 ( mol )
\(V_{H_2}=0,125.22,4=2,8l\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)\\
n_{HCl}=\dfrac{10,95}{36,5}=0,3\left(mol\right)\\
pthh:Mg+2HCl\rightarrow MgCl_2+H_2\\
LTL:\dfrac{0,1}{1}< \dfrac{0,3}{2}\)
=> HCl dư
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
a, \(n_{Mg}=\dfrac{3,6}{24}=0,15\left(mol\right);n_{HCl}=\dfrac{18,25}{36,5}=0,5\left(mol\right)\)
PTHH: Mg + 2HCl → MgCl2 + H2
Mol: 0,15 0,3
b, Ta có: \(\dfrac{0,15}{1}< \dfrac{0,5}{2}\) ⇒ Mg pứ hết, HCl dư
\(m_{HCldư}=\left(0,5-0,3\right).36,5=7,3\left(g\right)\)
c, \(V_{H_2}=0,15.22,4=3,36\left(l\right)\)
2.
a, \(n_P=\dfrac{6,2}{31}=0,2\left(mol\right)\)
PTHH: 4P + 5O2 ---to→ 2P2O5
Mol: 0,2 0,25 0,1
b, \(V_{O_2}=0,25.22,4=5,6\left(l\right)\)
c, \(m_{P_2O_5}=0,1.142=14,2\left(g\right)\)
d, \(V_{kk}=5,6.5=28\left(l\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)\)
PTHH: Mg + 2HCl --> MgCl2 + H2
_____0,1--->0,2------->0,1---->0,1
=> mHCl = 0,2.36,5 = 7,3(g)
b) mMgCl2 = 0,1.95 = 9,5 (g)
c) VH2 = 0,1.22,4 = 2,24(l)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Mg + 2HCl --> MgCl2 + H2
b) \(n_{Mg}=\dfrac{4,8}{24}=0,2\left(mol\right)\)
PTHH: Mg + 2HCl --> MgCl2 + H2
_____0,2--->0,4--------------->0,2
=> mHCl = 0,4.36,5 = 14,6 (g)
c) VH2 = 0,2.22,4 = 4,48 (l)
![](https://rs.olm.vn/images/avt/0.png?1311)
2Na + 2HCl -> 2NaCl + H2
2Na + H2SO4 -> Na2SO4 + H2
6Na + 2H3PO4 -> 2Na3PO4 + 3H2
2Al + 6HCl -> 2AlCl3 + 3H2
2Al + 3H2SO4 -> Al2(SO4)3 + 3H2
2Al + 2H3PO4 -> 2AlPO4 + 3H2
Mg + 2HCl -> MgCl2 + H2
Mg + H2SO4 -> MgSO4 + H2
3Mg + 2H3PO4 -> Mg3(PO4)2 + 3H2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)\)
PTHH: Mg + 2HCl --> MgCl2 + H2
_____0,1--->0,2------->0,1---->0,1
=> mHCl = 0,2.36,5 = 7,3(g)
b) mMgCl2 = 0,1.95 = 9,5 (g)
c) VH2 = 0,1.22,4 = 2,24(l)
thiếu đề