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![](https://rs.olm.vn/images/avt/0.png?1311)
a. \(Fe_2O_x+xH_2\rightarrow2Fe+xH_2O\)
b. \(n_{Fe}=\dfrac{m}{M}=\dfrac{1,05}{56}=0,01875\left(mol\right)\)
\(Fe_2O_x+xH_2\rightarrow2Fe+xH_2O\)
1 : 2
0,009375 : 0,01875
\(\Rightarrow M_{Fe_2O_x}=\dfrac{m}{n}=\dfrac{1,5}{0,009375}=160\) (g/mol)
\(\Rightarrow56.2+16x=160\)
\(\Rightarrow x=\dfrac{160-56.2}{16}=3\)
-Vậy CTHH của oxit sắt là Fe2O3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(CT:Fe_xO_y\)
\(Fe_xO_y+yH_2\underrightarrow{^{t^o}}xFe+yH_2O\left(1\right)\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\left(2\right)\)
\(n_{Fe}=n_{H_2\left(2\right)}=\dfrac{4.032}{22.4}=0.18\left(mol\right)\)
\(n_{H_2\left(1\right)}=\dfrac{y}{x}\cdot n_{Fe}=\dfrac{5.376}{22.4}=0.24\left(mol\right)\)
\(\Leftrightarrow\dfrac{y}{x}\cdot0.18=0.24\)
\(\Leftrightarrow\dfrac{x}{y}=\dfrac{3}{4}\)
\(CT:Fe_3O_4\)
\(m_{Fe_3O_4}=\dfrac{0.18}{3}\cdot232=13.92\left(g\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{HCl} =\dfrac{52,16.1,05.10\%}{36,5} = 0,15(mol)\\ Fe_xO_y + 2yHCl \to xFeCl_{\dfrac{2y}{x}} + yH_2O\\ n_{Fe_xO_y} = \dfrac{n_{HCl}}{2y} = \dfrac{0,075}{y}(mol)\\ \Rightarrow \dfrac{0,075}{y}.(56x + 16y) = 4\\ \Rightarrow \dfrac{x}{y} =\dfrac{2}{3}\)
Vậy CTHH của oxit : Fe2O3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{Fe_xO_y}=\dfrac{32}{56x+16y}\left(mol\right)\)
PTHH: FexOy + yH2 --to--> xFe + yH2O
\(\dfrac{32}{56x+16y}\)----------->\(\dfrac{32x}{56x+16y}\)
=> \(\dfrac{32x}{56x+16y}=\dfrac{22,4}{56}=0,4\)
=> \(\dfrac{x}{y}=\dfrac{2}{3}\)
=> CTHH: Fe2O3
\(n_{Fe}=\dfrac{22,4}{56}=0,4mol\)
\(Fe_xO_y+yH_2\rightarrow xFe+yH_2O\)
\(\dfrac{0,4}{x}\) 0,4
\(\Rightarrow M=\dfrac{32}{\dfrac{0,4}{x}}=80x\)
Mà \(M_{Fe_xO_y}=56x+16y=80x\Rightarrow16y=24x\Rightarrow\dfrac{x}{y}=\dfrac{16}{24}=\dfrac{2}{3}\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\Rightarrow Fe_2O_3\)
a. \(Fe_xO_y+yH_2\rightarrow xFe+yH_2O\)
b. \(n_{Fe}=\dfrac{m}{M}=\dfrac{1,05}{56}=0,01875\)
\(Fe_xO_y+yH_2\rightarrow xFe+yH_2O\)
1 : x
\(\dfrac{0,01875}{x}\) : 0,01875
\(\Rightarrow M_{Fe_xO_y}=\dfrac{m}{n}=\dfrac{1,5}{\dfrac{0,01875}{x}}=80x\)
\(\Rightarrow56x+16y=80x\)
\(\Rightarrow16y=24x\)
\(\Rightarrow\dfrac{x}{y}=\dfrac{16}{24}=\dfrac{2}{3}\)
\(\Rightarrow x=2;y=3\)
-Vậy CTHH của oxit sắt là Fe2O3