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![](https://rs.olm.vn/images/avt/0.png?1311)
Chọn đáp án B
@ Lời giải:
+ Mối liên hệ giữa cường độ điện trường và hiệu điện thế giữa hai bản kim loại:
![](https://rs.olm.vn/images/avt/0.png?1311)
Chọn đáp án B
@ Lời giải:
+ Mối liên hệ giữa cường độ điện trường và hiệu điện thế giữa hai bản kim loại:
![](https://rs.olm.vn/images/avt/0.png?1311)
Chọn B
Mối liên hệ giữa cường độ điện trường và hiệu điện thế giữa hai bản kim loại:
![](https://rs.olm.vn/images/avt/0.png?1311)
đáp án C
V A - V B = U A B = E . A B V M - V B = U M B = E . M B ⇒ V M - V B U A B = M B A B
⇒ V M - 10 120 = 0 , 6 1 ⇒ V M = 82 V
Câu 1:![2.10 to the power of 4.1.10 cubed equals 2.10 to the power of 7 space 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Áp dụng công thức
U=E.d=4000.0,02=80(V)
=> Chọn A
Câu 2:
Chọn gốc điện thế tại mặt đất
Hiệu điện thế giữa đám mây và mặt đất là:
U=Ed=
=> Chọn A