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![](https://rs.olm.vn/images/avt/0.png?1311)
a) CaC2 + 2H2O --> Ca(OH)2 + C2H2
C2H2 + H2 -Ni-> C2H4
C2H4 + H2O --> C2H5OH
C2H5OH + O2 -mg-> CH3COOH + H2O
CH3COOH + C2H5OH <-H2SO4đ,to-> CH3COOC2H5 + H2O
b) (-C6H10O5-)n + nH2O -axit-> nC6H12O6
C6H12O6 -mr-> 2C2H5OH + 2CO2
C2H5OH + O2 -mg-> CH3COOH + H2O
CH3COOH + C2H5OH <-H2SO4đ,to-> CH3COOC2H5 + H2O
CH3COOC2H5 + NaOH -to-> CH3COONa + C2H5OH
a/ CaC2 + 2H2O => Ca(OH)2 + C2H2
C2H2 + H2 => (Pd,to) C2H4
C2H4 + H2O => (140oC,H2SO4đ) C2H5OH
C2H5OH + O2 => (men giấm) CH3COOH + H2O
CH3COOH + C2H5OH => (H2SO4đ,to,pứ hai chiều) CH3COOC2H5 + H2O: pứ este hóa
![](https://rs.olm.vn/images/avt/0.png?1311)
\(CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\\ C_2H_2+H_2\xrightarrow[t^o]{Pd}C_2H_4\\ C_2H_4+H_2O\xrightarrow[t^o]{axit}C_2H_5OH\\ C_2H_5OH+O_2\underrightarrow{men,giấm}CH_3COOH+H_2O\\ CH_3COOH+C_2H_5OH\xrightarrow[t^o]{H_2SO_{4\left(đ\right)}}CH_3COOC_2H_5+H_2O\)
\(CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\)
\(C_2H_2+H_2\rightarrow\left(t^o,Pd\right)C_2H_4\)
\(C_2H_4+H_2O\rightarrow\left(t^o,axit\right)C_2H_5OH\)
\(C_2H_5OH+O_2\rightarrow\left(men.giấm\right)CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH\rightarrow\left(t^o,H_2SO_4\left(đ\right)\right)CH_3COOC_2H_5+H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Chuỗi 1:
\(\left(1\right)CaCO_3\rightarrow\left(t^o\right)CaO+CO_2\\ \left(2\right)CaO+3C\rightarrow\left(2000^oC,lò.điện\right)CaC_2+CO\uparrow\\ \left(3\right)CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\\ \left(4\right)C_2H_2+H_2\rightarrow\left(Ni,t^o\right)C_2H_4\\ \left(5\right)C_2H_4+H_2O\rightarrow\left(t^o,H^+\right)C_2H_5OH\\ \left(6\right)C_2H_5OH+2NaOH+CH_3COOH\rightarrow CH_3COONa+C_2H_5ONa+2H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2C_4H_{10}+5O_2\underrightarrow{t^o}4CH_3COOH+2H_2O\)
\(CH_3COOH+C_2H_5OH\xrightarrow[H_2SO_4đặc]{t^o}CH_3COOC_2H_5+H_2O\)
CH3COOC2H5 + NaOH \(\rightarrow\) CH3COONa + C2H5OH
\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)
CaC2 + 2H2O\(\rightarrow\) C2H2 + Ca(OH)2
\(C_2H_2+H_2\underrightarrow{t^o}C_2H_4\)
\(C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\)
\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)
CO2 + 2NaOH \(\rightarrow\) Na2CO3 + H2O
2CH3COOH + Na2CO3 \(\rightarrow\) 2CH3COONa + CO2 + H2O
![](https://rs.olm.vn/images/avt/0.png?1311)
$C_2H_4 + H_2O \xrightarrow{t^o,xt} C_2H_5OH$
$C_2H_5OH+ O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH \buildrel{{H_2SO_4,t^o}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + KOH \to CH_3COOK + C_2H_5OH$
\(C_2H_4+H_2O\rightarrow C_2H_5OH\)
\(C_2H_5OH+\left(CH_3CO\right)_2O\rightarrow CH_3COOH+CH_3COOC_2H_5\)
\(CH_3COOH+C_2H_5ONa\rightarrow NaOH+CH_3COOC_2H_5\)
\(KOH+CH_3COOC_2H_5\rightarrow C_2H_5OH+CH_3COOK\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Theo chiều từ trái sang, từ trên xuống nhé
\(C_2H_2+H_2\underrightarrow{t^o,Pd/PbCO_3}C_2H_4\)
\(C_2H_4+H_2O\underrightarrow{H^+,t^o}C_2H_5OH\)
\(C_2H_5OH+O_2\underrightarrow{men.giấm}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH\underrightarrow{H_2SO_{4\left(đ\right)},t^o}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+NaOH\underrightarrow{t^o}CH_3COONa+C_2H_5OH\)
\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)
\(2CH_3COOH+MgO\rightarrow\left(CH_3COO\right)_2Mg+H_2O\)
\(C_2H_2+H_2\xrightarrow[t^o]{Pd}C_2H_4\\ C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\\ C_2H_5OH+O_2\underrightarrow{men.giấm}CH_3COOH\\ CH_3COOH+C_2H_5OH\xrightarrow[t^o]{H_2SO_4đặc}CH_3COOC_2H_5+H_2O\\ CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH\\ C_2H_4+Br_2\rightarrow C_2H_4Br_2\\ 2CH_3COOH+Mg\rightarrow\left(CH_3COO\right)_2Mg+H_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(1\right)\) \(CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\)
\(\left(2\right)\) \(C_2H_2+H_2\underrightarrow{Pd,t^o}C_2H_4\)
\(\left(3\right)\) \(C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\)
\(\left(4\right)\) \(C_2H_5OH+O_2\underrightarrow{mengiấm}CH_3COOH+H_2O\)
\(\left(5\right)\) \(CH_3COOH+C_2H_5OH⇌^{H_2SO_4đ,t^o}CH_3COOC_2H_5+H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Theo chiều từ trái sang, từ trên xuống nhé
\(C_2H_2+H_2\underrightarrow{t^o,Pd,PbCO_3}C_2H_4\)
\(C_2H_4+H_2O\underrightarrow{H^+,t^o}C_2H_5OH\)
\(C_2H_5OH+O_2\underrightarrow{men.giấm}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH\underrightarrow{H_2SO_{4\left(đ\right)},t^o}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+NaOH\underrightarrow{t^o}CH_3COONa+C_2H_5OH\)
\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)
\(2C_2H_5OH+2Na\rightarrow2C_2H_5ONa+H_2\)
\(2CH_3COOH+CuO\rightarrow\left(CH_3COO\right)_2Cu+H_2O\)
\(CH_3COOC_2H_5+NaOH\underrightarrow{t^o}CH_3COONa+C_2H_5OH\)
\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)
\(C_2H_2+C_2H_4\xrightarrow[t^o]{Pd\text{/}PdCO_3}C_2H_4\\ C_2H_4+H_2O\xrightarrow[H^+]{t^o}C_2H_5OH\\ C_2H_5OH+O_2\underrightarrow{\text{men giấm}}CH_3COOH+H_2O\\ CH_3COOH+C_2H_5OH\xrightarrow[t^o]{H_2SO_{4\left(đặc\right)}}CH_3COOC_2H_5+H_2O\\ CH_3COOC_2H_5+NaOH\rightarrow CH_3COONa+C_2H_5OH\)
\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\\ C_2H_5OH+Na\rightarrow C_2H_5ONa+\dfrac{1}{2}H_2\\ 2CH_3COOH+CuO\rightarrow\left(CH_3COO\right)_2Cu+H_2O\\ CH_3COOC_2H_5+KOH\rightarrow CH_3COOK+C_2H_5OH\\ C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)