![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : \(1^2+2^2+3^2+......+10^2=385\)
\(2^2\left(1^2+2^2+3^2+......+10^2\right)=2^2.385\)
\(2^2+4^2+6^2+.....+20^2=4.385\)
\(2^2+4^2+6^2+.....+20^2=1540\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=2^2+4^2+....+20^2=?\)
\(=\left(2.1\right)^2+\left(2.2\right)^2+\left(2.3\right)^2+....+\left(2.10\right)^2\)
\(=2^2.1^2+2^2.2^2+2^2.2^3+...+2^2.10^2\)
\(=2^2.\left(1^2+2^2+3^2+...+10^2\right)\)
\(=2^2.385\)
\(=4.385\)
\(=1540\)
S=22+42+...+202
=> 1/2 .S=12+22+...+102
=> 1/2 .S=385
=> S = 385 . 2
=> S = 770
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : S = 22 + 42 + 62 + .... + 202
= 12 . 22 + 22. 22 + 22 . 32 + .... + 22. 102
= 22.(12 + 22 + 32+ .... + 102)
Mà 12 + 22 + 32+ .... + 102 = 385
=> 22 . (12 + 22 + 32+ .... + 102) = 22 . 385 = 4 . 385 = 1540
Vậy S = 1540
S = 22 + 42 + 62 + ........ + 202
= 12. 22 + 22.22 + 32.22+ ........ + 102.22
= 22.(12 + 22 + 32+..........+ 102)
= 4.385
= 1540
![](https://rs.olm.vn/images/avt/0.png?1311)
\(10^9+10^8+10^7=10^6.10^3+10^6.10^2+10^6.10=10^6\left(1000+100+10\right)=10^6.1110\)
\(=10^6.222.5\) (ĐPCM)
\(S=2^2.1+2^2.2^2+2^2.3^2+....+2^2.10^2\)
\(S=2^2.\left(1^2+2^2+3^2+...+10^2\right)\)
\(S=4.385=1540\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt A = 12 + 22 + 32 + ... + 102 = 385
=> 62A = 62.(12 + 22 + 32 + ... + 102)
= (6.1)2 + (6.2)2 + ... + (6.10)2
= 62 + 122 + 182 +...+ 602 = S
hay 62.385 = S
Vậy S = 62.385 = 13860.
Đặt \(S=1^2+2^2+3^2+...+10^2\)
\(\Rightarrow S.6^2=1^2.6^2+2^2.6^2+3^2.6^2+....+10^2.6^2\)
\(S.6^2=1.6^2+2.6^2+3.6^2+...+10.6^2\)
\(S.6^2=6^2+12^2+18^2+...+60^2\)
\(S.6^2=S=385.6^2\)
\(\Rightarrow S=385.4=1540\)
Vậy:..... Tự tính nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
S = 2^2 + 4^2 +.. +20^2
= 2^2 . 1 +2^2 .2^2 +...+2^2 .10^2
= 2^2 ( 1+ 2^2 +...+10^2)
= 4 . S
= 4. 385
= 1540
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 12+22+32+...+92+102=385
22+42+62+...+202=22.12+22.22+22.32+....+22.92+22.102
=22.(11+22+32+....+92+102)
=4.385
=1540
S = 22 + 42 + 62 + ... + 202
= (2.1)2 + (2.2)2 + (2.3)2 ... (2.10)2
= 22.12 + 22.22 + 22.32 + ... + 22.102
= 22 (12 + 22 + ... + 102 )
= 4 . 385 = 1540
![](https://rs.olm.vn/images/avt/0.png?1311)
8x : 2x = 4
<=> (8 : 2)x = 4
<=> 4x = 4
<=> x = 1
S = 22 + 42 + 62 + ... + 202
S = (22 + 42 + 62 + ... + 202)
S =22.(12 + 22 + 32 + ... + 102 )
S = 4. 385 = 1540
/Tìm X biết
\(8^x:2^x=4\)
\(\Leftrightarrow\left(8:2\right)^x=4\)
\(\Rightarrow4^x=4^1\)
\(\Rightarrow x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt T= 12 +22+32+.....+102
=> T x 62 = 12. 62 + 22. 62 + 32. 62 +...+102. 62
T x 62 = (1.6)2 + (2.6)2 +(3.6)2 + ... + (10.6)2
T x 62 = 62 +122 +182 +...+ 602
T x 62 = S = 385. 62
=> S = 385. 4 =1540
=1540
Bài làm
Ta thấy : \(2^2=4=4.1^2\)
\(4^2=16=4.2^2\)
\(6^2=36=4.3^2\)
.......
\(20^2=400=4.10^2\)
\(\Rightarrow S=2^2+4^2+6^2+....+20^2\)
\(=4.\left(1^2+2^2+3^2+.....+10^2\right)\)
\(=4.385\)
\(=1540\)
~ Hok Tốt ~