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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta co : 13 + 23 +...+ 103 = 3025
=>2.13 + 2.23+...+2.103 = 2.3025
=> 26 + 46 +...+ 206 =6050
=> [23 + 3] + [ 43 + 3] + ...+ [203 + 3] =6050
=> 23 + 43 +... 203 = 6050 - 3.10
=> S = 6020
Ta có :
13 + 25 + ... + 103 = 3025
=> 2,13 + 2,23 + .... + 2,103 = 2,3025
=> 26 + 46 + .... + 206 = 6050
=> ( 23 + 3 ) + ( 43 + 3 ) + ..... + ( 203 + 3 ) = 6050
=> 23 + 43 + .... 203 = 6050 - 3,10
=> S = 6020
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có: 13 + 23 + 33 +...+103 = 3025
⇒ 2.13 + 2.23 +..+ 2.103 = 2.3025
⇒ 26 + 46 +..+206 = 6050
⇒ (23+3) + (43+3) +..+(203+3) = 6050
⇒ 23 + 43 +..+203 = 6050 - 3.10
⇒ S = 6020
ta có: 13 + 23 + 33 +...+103 = 3025
⇒ 2.13 + 2.23 +..+ 2.103 = 2.3025
⇒ 26 + 46 +..+206 = 6050
⇒ (23+3) + (43+3) +..+(203+3) = 6050
⇒ 23 + 43 +..+203 = 6050 - 3.10
⇒ S = 6020
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
Đặt A= 13+23+...+103= 3025
2A=26+46+...+206
2A=(23+3)+(43+3)+...+(203+3)=6050
S=6050-(3.10)=6020
Ko hiểu cứ hỏi mình
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1^3+2^3+3^3+...+10^3=3025\\ S=2^3+4^3+6^3+...+20^3\\ =\left(2\cdot1\right)^3+\left(2\cdot2\right)^3+\left(2\cdot3\right)^3+...+\left(2\cdot10\right)^3\\ =2^3\cdot1^3+2^3\cdot2^3+2^3\cdot3^3+...+2^3\cdot10^3\\ =2^3\left(1^3+2^3+3^3+...+10^3\right)\\ =8\cdot3025\\ =24200\)
Ta có:
\(S=2^3+4^3+6^3+...+20^3.\)
\(\Rightarrow S=2^3.1^3+2^3.2^3+2^3.3^3+...+2^3.10^3.\)
\(\Rightarrow S=2^3\left(1^3+2^3+3^3+...+10^3\right).\)
\(\Rightarrow S=8.3025=24200.\)
Vậy \(S=24200.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
S = 13+10+23+20+33+30+...+103+100
S = 13+23+33+...+103+10.100
S = 3025+1000
S = 4025
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(S=23+43+63+...+203\)
\(S=\left(10+13\right)+\left(20+23\right)+...+\left(100+103\right)\)
\(S=\left(10+20+...+100\right)+\left(13+23+...+103\right)\)
\(S=10\cdot\frac{10\cdot11}{2}+3025\)
\(S=550+3025=3575\)
Ta có: 13 + 23 + ... + 103 = 3025
=> 2 . 13 + 2 . 23 + ... + 2 . 103 = 2 . 3025
=> 26 + 46 + ... + 206 = 6050
=> ( 23 + 3 ) + ( 43 + 3 ) + ... + ( 203 + 3 ) = 6050
=>23 + 43 + ... + 203 = 6050 - 3 . 10
=>S = 6020
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:S=23+43+63+…+203
=>S=23+43+63+…+203+3+3+3+…+3-3-3-3-…-3
=>S=(23+3)+(43+3)+(63+3)+…+(203+3)-(3+3+3+…+3)
=>S=26+46+66+…+206-(3+3+3+…+3)
Từ 26 đến 206 có:
(206-26):20+1=10(số)
=>S=26+46+66+…+206-3.10
=>S=2.(13+23+33+…+103)-30
mà 13+23+33+…+103=3025
=>S=2.3025-30
=>S=6050-30
=>S=6020
Vậy S=6020.