K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

4 tháng 10 2020

\(M=4.6\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)\(=\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)\(=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)=\left(5^{16}-1\right)\left(5^{16}+1\right)=5^{32}-1\)

Vậy M <N

15 tháng 9 2019

\(B=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(=5^{32}-1< 5^{32}\)

Vậy \(B< A\)

3: =(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)

=(5^4-1)(5^4+1)(5^8+1)(5^16+1)

=(5^8-1)(5^8+1)(5^16+1)

=(5^16-1)(5^16+1)

=5^32-1

4:

D=(4^4-1)(4^4+1)(4^8+1)*....*(4^64+1)

=(4^8-1)(4^8+1)*...*(4^64+1)

=...

=4^128-1

5: =(5^2-1)(5^2+1)(5^4+1)*...*(5^128+1)+(5^256-1)

=(5^4-1)(5^4+1)*...*(5^128+1)+5^256-1

=5^256-1+5^256-1

=2*5^256-2

7 tháng 7 2023

thsu là rất ngưỡng mộ anh ạ 🥹 em mấy lần off vì quá nhác nhưng lần nào ngoi lại lên cũng thấy anh cày chăm chỉ quá tr 😭

30 tháng 7 2019

\(B=10^2+8^2+...+2^2-\left(9^2+7^2+5^2+3^2+1^2\right)\)

\(B=\left(10^2-9^2\right)+\left(8^2-7^2\right)+...+\left(2^2-1^2\right)\)

\(B=\left(10+9\right)\left(10-9\right)+\left(8+7\right)\left(8-7\right)+...+\left(2-1\right)\left(2+1\right)\)

\(B=19+15+...+3\)

Đến đây dễ rồi. Câu a) đang suy nghĩ

31 tháng 7 2019

\(A=1+\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+4\cdot\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5^{16}-1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(4A=4+\left(5^{32}-1\right)\left(5^{32}+1\right)\)

\(4A=4+5^{64}-1\)

\(4A=5^{64}+3\)

\(A=\frac{5^{64}+3}{4}\)

10 tháng 8 2019

\(B=\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)

\(B=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right).\frac{1}{24}\)

\(B=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right).\frac{1}{24}\)

\(B=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right).\frac{1}{24}\)

\(B=\left(5^{16}-1\right)\left(5^{16}+1\right)\left(5^{32}+1\right).\frac{1}{24}\)

\(B=\left(5^{32}-1\right)\left(5^{32}+1\right).\frac{1}{24}\)

\(B=\left(5^{64}-1\right).\frac{1}{24}\)

\(B=\frac{5^{64}-1}{24}\)

6 tháng 8 2019

a)\(\left(2+1\right)\left(2^2+1\right)....\left(2^{256}+1\right)-1\)

\(=\left(2-1\right)\left(2+1\right)\left(2^2+1\right)...\left(2^{256}+1\right)-1\)

\(=\left(2^2-1\right)\left(2^2+1\right)...\left(2^{256}+1\right)-1\)

Tiếp tục như thế, ta được:

\(=\left(2^{256}-1\right)\left(2^{256}+1\right)-1=2^{512}-1-1=2^{512}-2\)

b) \(24\left(5^2+1\right)\left(5^4+1\right)...\left(5^{32}+1\right)-5^{64}\)

\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)...\left(5^{32}+1\right)-5^{64}\)

\(=\left(5^4-1\right)\left(5^4+1\right)...\left(5^{32}+1\right)-5^{64}\)

Tiếp tục như thế, ta được:

\(=\left(5^{32}-1\right)\left(5^{32}+1\right)-5^{64}=5^{64}-1-5^{64}=-1\)

6 tháng 8 2019

\(\left(2+1\right).\left(2^2+1\right)....\left(2^{256}+1\right)-1\)

\(\left(2-1\right).\left(2+1\right).\left(2^2+1\right).....\left(2^{256}+1\right)-1\)

\(=\left(2^2-1\right).\left(2^2+1\right)....\left(2^{256}+1\right)-1\)

\(=\left(2^{256}-1\right).\left(2^{256}+1\right)+1=2^{512}+1\)

12 tháng 10 2017

\(A=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(A=\dfrac{24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(A=\dfrac{\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(A=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(A=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(A=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)

\(A=\dfrac{5^{32}-1}{2}\)

12 tháng 10 2017

\(A=\left|2x+4\right|+\left|2x+6\right|+\left|2x+8\right|\)

\(A=\left|2x+4\right|+\left|2x+8\right|+\left|2x+6\right|\)

\(A=\left|2x+4\right|+\left|-2x-8\right|+\left|2x+6\right|\)

\(A\ge\left|2x+4-2x-8\right|+\left|2x+6\right|\)

\(A\ge4+\left|2x+6\right|\)

\(\left|2x+6\right|\ge0\) nên \(A\ge4\)

Dấu "=" xảy ra khi:

\(\left\{{}\begin{matrix}2x+4\le0\\2x+6=0\\2x+8\ge0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x\le-4\\2x=-6\\2x\ge-8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\le-2\\x=-3\\x\ge-4\end{matrix}\right.\)

Vậy \(x=-3\)

10 tháng 10 2019

câu a là hằng đẳng thức luôn

A=(2x+4)^2

B khai triển tung tóe ra thì phần sau triệt tiêu hết còn 4(a^2+b^2+c^2)

câu c cảm giác sai đề vì mấy câu này phải là (3x)^ ms ra hdt chứ nhỉ

10 tháng 9 2017

Đặt :

\(A=\)\(12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Leftrightarrow2A=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(=\left(5^{16}+1\right)\left(5^{16}-1\right)\)

\(=5^{32}-1\)

\(\Leftrightarrow A=\frac{5^{32}-1}{2}\)

17 tháng 7 2016

\(A=\frac{1}{2}\left(5^2-1\right)\) \(\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\) 

A= 1/2(5^4-1)(5^4+1)(5^8+1)(5^16+1)

Làm tương tự còn:

A=1/2(5^16-1)(5^16+1)=1/2(5^32-1)