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2 tháng 6 2015

a) \(\sqrt{0,09}-\sqrt{0,64}=\frac{-1}{2}=-0,5\)

b) \(0,1\cdot\sqrt{225}-\sqrt{\frac{1}{4}}=0,1\cdot15-\frac{1}{2}=1\)

c) \(\sqrt{0,36}\cdot\sqrt{\frac{25}{16}+\frac{1}{4}}=\frac{3\sqrt{29}}{20}\)

d) đề baì có sai ko ban?

21 tháng 10 2018

a) = \(\frac{7}{2}\)

b) = \(\frac{643}{64}\)

c) = 0

2 tháng 12 2017

\(\sqrt{\frac{25}{4}}+\left(\sqrt{\frac{1}{2}}\right)^2:\left(\frac{-\sqrt{9}}{4}\right).\sqrt{\frac{16}{81}}-4^2-\left(-2\right)^3\)

\(=\frac{5}{2}+\frac{1}{2}:\frac{-3}{4}.\frac{4}{9}-16+8\)

\(=\frac{5}{2}-\frac{8}{27}-8\)

\(=\frac{-313}{54}\)

2 tháng 12 2017

-313/54

Bài 1:

a) Ta có: \(\left(0.125\right)\cdot\left(-3\cdot7\right)\cdot\left(-2\right)^3\)

\(=\frac{1}{8}\cdot\left(-21\right)\cdot\left(-8\right)\)

\(=\frac{1}{8}\cdot168\)

\(=21\)

b) Ta có: \(\sqrt{36}\cdot\sqrt{\frac{25}{16}}+\frac{1}{4}\)

\(=\sqrt{36\cdot\frac{25}{16}}+\frac{1}{4}\)

\(=\sqrt{\frac{225}{4}}+\frac{1}{4}\)

\(=\frac{15}{2}+\frac{1}{4}\)

\(=\frac{31}{4}\)

c) Ta có: \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac{2}{5}\)

\(=\frac{2}{9}:\frac{5}{9}-\frac{7}{5}\)

\(=\frac{2}{5}-\frac{7}{5}=-1\)

d) Ta có: \(0,1\cdot\sqrt{225}\cdot\sqrt{\frac{1}{4}}\)

\(=0,1\cdot15\cdot\frac{1}{2}=\frac{3}{4}\)

6 tháng 7 2022

hay quá eoeo cảm ơn bạn nhé yeu

23 tháng 12 2016

a là âm 2.671428571

5 tháng 4 2017

a, \(-\frac{187}{70}\)

b,\(\frac{27}{70}\)

c,\(\frac{53}{14}\)

d,\(\frac{27}{4}\)

e,1

f,\(\frac{23}{4}\)

g,-1

i,6

k,315

l,\(\frac{9}{2}\)
 

\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)

\(=\frac{1}{3}+\frac{1}{4}\)

\(=\frac{7}{12}\)

\(\sqrt{4+36+81}\)

\(=\sqrt{121}\)

\(=\pm11\)

25 tháng 11 2015

= 1/2.8 + 20.0,1 - 7 - 4,46632421

= 4 + 2 - 7 - 4,46632421

= -5,46632421

8 tháng 7 2015

\(\left(\sqrt{\frac{36}{81}}+\sqrt{\frac{16}{25}}\right):\sqrt{\frac{100}{36}}=\left[\sqrt{\left(\frac{6}{9}\right)^2}+\sqrt{\left(\frac{4}{5}\right)^2}\right]:\sqrt{\left(\frac{10}{6}\right)^2}\)

=\(\left(\frac{6}{9}+\frac{4}{5}\right):\frac{10}{6}=\left(\frac{2}{3}+\frac{4}{5}\right).\frac{3}{5}=\left(\frac{10}{15}+\frac{12}{15}\right).\frac{3}{5}=\frac{22}{15}.\frac{3}{5}=\frac{22}{25}\)

4 tháng 8 2019

a) \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac{2}{5}\)

\(=\frac{2}{9}:\frac{5}{9}-\frac{7}{5}\)

\(=\frac{2}{5}-\frac{7}{5}\)

\(=-1.\)

b) \(\sqrt{36}.\sqrt{\frac{25}{16}}+\frac{1}{4}\)

\(=6.\frac{5}{4}+\frac{1}{4}\)

\(=\frac{15}{2}+\frac{1}{4}\)

\(=\frac{31}{4}.\)

c) \(1\frac{1}{2}+\frac{4}{7}:\left(-\frac{8}{9}\right)\)

\(=\frac{3}{2}+\frac{4}{7}:\left(-\frac{8}{9}\right)\)

\(=\frac{3}{2}+\left(-\frac{9}{14}\right)\)

\(=\frac{6}{7}.\)

d) \(1,17-0,4.\left(\frac{1}{2}\right)^2-\frac{1}{-5}\)

\(=\frac{117}{100}-\frac{2}{5}.\frac{1}{4}-\left(-\frac{1}{5}\right)\)

\(=\frac{117}{100}-\frac{1}{10}+\frac{1}{5}\)

\(=\frac{107}{100}+\frac{1}{5}\)

\(=\frac{127}{100}.\)

Chúc bạn học tốt!

4 tháng 8 2019

a, \(\frac{4}{81}:\sqrt{\frac{25}{81}-1\frac{2}{5}}\)

\(\Rightarrow\frac{4}{81}:\frac{5}{9}-\frac{7}{5}\)

\(\Rightarrow\frac{4}{81}.\frac{9}{5}-\frac{7}{5}\)

\(\Rightarrow\frac{4}{9}.\frac{1}{5}-\frac{7}{5}\)

\(\Rightarrow\frac{-59}{45}\)

b,\(\sqrt{36}.\sqrt{\frac{25}{16}+\frac{1}{4}}\)

\(\Rightarrow6.\frac{5}{4}+\frac{1}{4}\)

\(\Rightarrow\frac{15}{2}+\frac{1}{4}\)

\(\Rightarrow\frac{31}{4}\)

c,\(1\frac{1}{2}+\frac{4}{7}:\frac{-8}{9}\)

\(\Rightarrow\frac{3}{2}-\frac{4}{7}.\frac{-8}{9}\)

\(\Rightarrow\frac{3}{2}-\frac{9}{14}\)

\(\Rightarrow\frac{6}{7}\)

d, \(1,17-\left(0,4.\frac{1}{2}\right)^2-\frac{1}{5}\)

\(\Rightarrow\frac{117}{100}-\left(\frac{1}{5}\right)^2-\frac{1}{5}\)

\(\Rightarrow\frac{117}{100}-\frac{1}{25}-\frac{1}{5}\)

\(\Rightarrow\frac{93}{100}\)