Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -) Mai doesn't plays badminton after school
?) Does Mai play badminton after school?
b) -) She doesn't you out at the moment
?) Does she you out at the moment?
c) -) We don't after have a picnic on weekend
?) Do you after have a picnic on weekend?
d) -) The student aren't sitting in class
?) Are student sitting in class?
e) -) I can't play giutar
?) Can you play giutar?
Bạn ơi đề bài đáng ra là chuyển các câu sau sang phủ định và nghi vấn chứ
phays=plays
A) Mai don't play badminton after school
Is Mai play badminton after school ?
B) She you out not at the moment
Are you she out at the moment ?
C) We not after have a picnic on weekend
Are we after have picnic on weekend ?
D) The student not are sitting in class
Is student sitting in class ?
E) I can't play giutar
Can I play giutar ?
![](https://rs.olm.vn/images/avt/0.png?1311)
1. She won't be happy
Will she be happy
2. My family does not often go for a picnic on the weekend
Does my family often go for a picnic on the weekend
![](https://rs.olm.vn/images/avt/0.png?1311)
1.She usually leaves home at seven o'clock.
2.Next week we will go camping.
3.I will wait for you outside the cinema.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 6:
Xét ΔOAC vuông tại A và ΔOBD vuông tại B có
OA=OB
\(\widehat{AOC}=\widehat{BOD}\)(hai góc đối đỉnh)
Do đó: ΔOAC=ΔOBD
=>OC=OD
Bài 7:
a: Ta có: \(\widehat{DAB}+\widehat{BAC}+\widehat{CAE}=180^0\)
=>\(\widehat{DAB}+\widehat{CAE}+90^0=180^0\)
=>\(\widehat{DAB}+\widehat{CAE}=90^0\)
mà \(\widehat{DAB}+\widehat{DBA}=90^0\)
nên \(\widehat{DBA}=\widehat{CAE}\)
Xét ΔABD vuông tại A và D và ΔCAE vuông tại E có
AB=AC
\(\widehat{DBA}=\widehat{EAC}\)
Do đó: ΔABD=ΔCAE
b: ta có: ΔABD=ΔCAE
=>DB=AE và AD=CE
DB+CE=DA+AE=DE
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x=3y=5z\Rightarrow\frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{\frac{1}{5}}\)
Áp dụng t/c dãy tỉ số = nhau ta có:
\(\frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{\frac{1}{5}}=\frac{x+y+z}{\frac{1}{2}+\frac{1}{3}+\frac{1}{5}}=\frac{-33}{\frac{31}{30}}=-\frac{990}{31}\)
\(\frac{x}{\frac{1}{2}}=-\frac{990}{31}\Rightarrow x=-\frac{495}{31}\)
\(\frac{y}{\frac{1}{3}}=-\frac{990}{31}\Rightarrow y=-\frac{330}{31}\)
\(\frac{z}{\frac{1}{5}}=-\frac{990}{31}\Rightarrow z=-\frac{198}{31}\)
Vậy ...
![](https://rs.olm.vn/images/avt/0.png?1311)
Có: \(2x=3y=5z\)
=> \(\frac{2x}{30}=\frac{3y}{30}=\frac{5z}{30}\)
=> \(\frac{x}{15}=\frac{y}{10}=\frac{z}{6}\)
Áp dụng tc của dãy tỉ số bằng nhau ta có:
\(\frac{x}{15}=\frac{y}{10}=\frac{z}{6}=\frac{x+y+z}{15+10+6}=\frac{-33}{31}\)
=> \(\begin{cases}x=-\frac{495}{31}\\y=-\frac{330}{31}\\z=-\frac{198}{31}\end{cases}\)
a) 2x = 3y = 5z
=> \(\frac{x}{3}=\frac{y}{5}=\frac{z}{2}\)
Áp dụng tính chất dãy tỉ số = nhau , ta có :
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{2}=\frac{x+y+z}{3+5+2}=\frac{-33}{10}\)
=> x = 3.(-33/10) = -99/10
y = 5.(-33/10) = -165/10
z = 2.(-33/10) = -66/10
![](https://rs.olm.vn/images/avt/0.png?1311)
36. yet
37. yet
38. yet
39. yet
40. already
41. yet
42. already
43. yet
44. already
45. yet
Mik ko cs thoi gian nen chi viet nhu the nay thoi nha
a) Mai plays badminton after school
( - ) Mai doesn't play badminton after school .
( ? ) Does Mai play badminton after school ?
b) She you out at the moment
( - ) She doesn't you out at the moment
( ? ) Does she you out at the moment
c) we often have a picnic on weekend
( - ) we don't often have a picnic on weekend
( ? ) Do you often have a picnic on weekend
d) The students are sitting in class
( - ) The students aren't sitting in class
( ? ) Are the students sitting in class
e) I can play giutar
( - ) I can't play giutar
( ? ) Can you play giutar
bạn ơi đề bài phải là chuyển các câu sau sang phủ định và nghi vấn , khẳng định là câu bạn đặt ra ế
tk mình nhá
mình ko hiểu đề bài ( đáng ra là phủ định) và câu 2
1. Mai doesn't play badminton after school
2.
3. We doesn't often have a picnic on weekend.
4. The student aren't sitting in class.
5. I can't play guitar.