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a, \(\frac{6}{7}.\frac{16}{15}.\frac{7}{6}.\frac{21}{32}=\frac{6}{7}.\frac{7}{6}.\frac{16}{15}.\frac{21}{32}\)=\(1.\frac{16}{15}.\frac{21}{32}=\frac{7}{5.2}=\frac{7}{10}\)
Phần b T2
c,\(\frac{7}{4}.\frac{11}{21}+\frac{11}{21}.\frac{5}{4}=\frac{11}{21}.\left(\frac{7}{4}+\frac{5}{4}\right)\)=\(\frac{11}{21}.3=\frac{11}{7}\)
\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2001}{2002}.\frac{2002}{2003}=\frac{1.2.3.....2001.2002}{2.3.4.....2002.2003}=\frac{1}{2003}\)
b . 3/7 . 16/33 + 16/33 . 4/7
= 16/33 . ( 3/7 + 4/7 )
= 16/33 . 7/7
= 16/33 . 1
= 16/33
c2 3/7 . 16/33 + 16/33 . 4/7
= 16/77 + 64/231
= 48/231 + 64/231
= 112/231
= 16/33
chúc em học giỏi !!!
a . 5/24 . 5/12 . 24
= ( 5/24 . 24 ) .5/12
= 5 . 5/12
= 25/12
C2 : 5/24 . 5/12 . 24
= 5/24 . ( 5/12 . 24 )
= 5/24 . 10
= 50/24
= 25/12
\(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}.\frac{5}{6}:\frac{2}{6}+2019\)
=\(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}.\frac{5}{6}.\frac{6}{2}+2019\)
=\(\frac{2.3.4.5.6}{3.4.5.6.2}+2019\)
=\(1+2019\)
=\(2020\)
\(=\frac{16}{15}+\frac{28}{5}+\frac{22}{15}\)
\(=\frac{122}{15}\)
\(\frac{16}{15}+\frac{28}{5}+\frac{44}{15}\\ =\frac{16}{15}+\frac{84}{15}+\frac{44}{15}\\ =\frac{144}{15}\)
\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}=\frac{1\cdot2\cdot3\cdot4}{2\cdot3\cdot4\cdot5}=\frac{1}{5}\)
\(\frac{9}{20}.\frac{5}{12}=\frac{45}{240}=\frac{9}{48}=\frac{3}{16}\)
\(\frac{9}{20}\)\(.\)\(\frac{5}{12}\)= \(\frac{3.3}{4.5}\)\(.\)\(\frac{5}{3.4}\)= \(\frac{3}{16}\)
`5/9xx1/4+4/9xx3/12`
`=5/9xx1/4+4/9xx1/4`
`=1/4xx(5/9+4/9)`
`=1/4xx9/9`
`=1/4xx1`
`=1/4`
\(\frac{9}{36}=\frac{12}{48}\)
Ta có:
\(\frac{9}{36}=\frac{1}{4}\)
và \(\frac{12}{48}=\frac{1}{4}\)\
nên \(\frac{9}{36}=\frac{12}{48}\)