Question

[Nhung Tuyết]

Ai dễ thương giúp mình đc hông mình cần gấp , mình cảm ơn nhiều

Answer 1

[๖ۣۜDũ๖ۣۜN๖ۣۜG]

Câu 1:

a) \(V_{SO_2}=0,2.22,4=4,48\left(l\right)\)

b) \(n_{O_2}=\dfrac{1,5.10^{23}}{6.10^{23}}=0,25\left(mol\right)=>V_{O_2}=0,25.22,4=5,6\left(l\right)\)

c) \(n_{CO_2}=\dfrac{17,6}{44}=0,4\left(mol\right)=>V_{CO_2}=0,4.22,4=8,96\left(l\right)\)

Câu 2

a) \(m_{Fe}=0,5.56=28\left(g\right)\)

b) \(m_{KOH}=0,1.56=5,6\left(g\right)\)

c) \(n_{Al}=\dfrac{1,8.10^{23}}{6.10^{23}}=0,3\left(mol\right)=>m_{Al}=0,3.27=8,1\left(g\right)\)

d) \(n_{Mg}=\dfrac{2,4}{24}=0,1\left(mol\right)=>n_{NaOH}=0,1\left(mol\right)=>m_{NaOH}=0,1.40=4\left(g\right)\)

Câu 3

a) \(n_{Na_2SO_4}=\dfrac{26,5}{142}=\dfrac{53}{284}\left(mol\right)\)

b) \(n_{H_2S}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)

c) \(n_{Zn}=\dfrac{1,2.10^{23}}{6.10^{23}}=0,2\left(mol\right)\)