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a: \(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}=\dfrac{365}{365}=1\)
c: \(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)
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bạn sai rồi
Oh
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{9}=2\)
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\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{2}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\dfrac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.9}\)
\(=\dfrac{3^2.2^{36}}{2^{35}.3^2}\)
\(=2\)
\(A=\frac{2}{13}.\frac{5}{9}+\frac{2}{13}.\frac{4}{9}+\frac{11}{13}=\frac{2}{13}.\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{3}\)
\(=\frac{2}{13}.1+\frac{11}{13}\)
\(=\frac{2}{13}+\frac{11}{13}=1\)
\(A=\frac{2}{13}\cdot\frac{5}{9}+\frac{2}{13}\cdot\frac{4}{9}+\frac{11}{13}\)
\(A=\frac{2}{13}\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{13}\)
\(A=\frac{2}{13}\cdot1+\frac{11}{13}\)
\(A=\frac{2}{13}+\frac{11}{13}\)
\(A=\frac{13}{13}=1\)