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( 20152015/20162016 + 20172017/20162016 ) . x - 1 = 2016
2.x-1=2016
2x=2017
x=2017:2
x=1008,5
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Ta thấy:
A = \(\frac{20162017}{20162016}\) và B = \(\frac{20152016}{20152015}\)
A = \(\frac{20162016}{20162016}\)+ \(\frac{1}{20162016}\) = \(1\) + \(\frac{1}{20162016}\)
B = \(\frac{20152015}{20152015}\) + \(\frac{1}{20152015}\)= \(1\) + \(\frac{1}{20152015}\)
Vì: \(\frac{1}{20162016}\) \(< \) \(\frac{1}{20152015}\)
Nên: \(A\) \(< \) \(B\)
~ HokT~
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a = 2015 x 20162016
A = 2015 x 10001 x 2016
B = 2016 x 20152015
B = 2016 x 10001 x 2015
=> A = B
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a) 3150 = 32 . 75 = ( 32 ) 75 = 975
2225 = 23 . 75 = ( 23 ) 75 = 875
Vì 9 > 8 nên 975 > 875 hay 3150 > 2225
b) 201620 = 20162 . 10 = ( 20162 ) 10
2016201610 = giữ nguyên
ta thấy hai lũy thừa đã cùng số mũ là 10 , giờ ta so sánh hai cơ số
20162 = 2016 . 2016
20162016 = 2016 . 10001
Vì 2016 < 10001 nên 20162 < 20162016 hay 201620 < 2016201610
c) 222333 = 2223 . 111 = ( 2223 ) 111
333222 = 3332 . 111 = ( 3332 ) 111
2223 = ( 2 . 111 ) 3 = 23 . 1113 = 8 . 1113
3332 = ( 3 . 111 ) 2 = 32 . 1112 = 9 . 1112
=> 222333 > 333222
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\(B=2015.20162016-2016.20152015\)
\(B=2015.2016.10001-2016.2015.10001\)
\(B=0\)
Ủng hộ mk nha ^_^
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A=2016^2016+2/2016^2016-1>1
=>(2016^2016)+2/(2016^2016)-1<(2016^2016)+2-2/(2016^2016)-1-2=2016^2016/(2016^2016)-3=B