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a) \(x\left(x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)
b) \(\left(-7-x\right)\left(-x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}-7-x=0\\-x+5=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-7\\x=-5\end{matrix}\right.\)
c) \(\left(x+3\right)\left(x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\x-7=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=7\end{matrix}\right.\)
d) \(\left(x-3\right)\left(x^2+12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-3=0\\x^2+12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x^2=-12\text{(vô lý)}\end{matrix}\right.\)
\(\Rightarrow x=3\)
e) \(\left(x+1\right)\left(2-x\right)\ge0\)
\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x+1\ge0\\2-x\ge0\end{matrix}\right.\\\left[{}\begin{matrix}x+1\le0\\2-x\le0\end{matrix}\right.\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x\ge-1\\x\le2\end{matrix}\right.\\\left[{}\begin{matrix}x\le-1\\x\ge2\end{matrix}\right.\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}-1\le x\le2\\x\in\varnothing\end{matrix}\right.\)
\(\Rightarrow-1\le x\le2\)
f) \(\left(x-3\right)\left(x-5\right)\le0\)
\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x-3\le0\\x-5\ge0\end{matrix}\right.\\\left[{}\begin{matrix}x-3\ge0\\x-5\le0\end{matrix}\right.\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x\le3\\x\ge5\end{matrix}\right.\\\left[{}\begin{matrix}x\ge3\\x\le5\end{matrix}\right.\end{matrix}\right.\)
\(\Rightarrow3\le x\le5\)
a) =>\(\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)
b => \(\left[{}\begin{matrix}-7-x=0\\-x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-7\\x=5\end{matrix}\right.\)
d) => \(\left[{}\begin{matrix}x-3=0\\x^2+12=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x^2=-12\end{matrix}\right.\)(vô lí) => x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ \(\left(x-35\right)-120=0\)
\(\Leftrightarrow x-35=0+120\)
\(\Leftrightarrow x-35=120\)
\(\Leftrightarrow x=120+35\)
\(\Leftrightarrow x=155\)
Vậy ...
b/ \(124+\left(188-x\right)=217\)
\(\Leftrightarrow188-x=217-124\)
\(\Leftrightarrow188-x=93\)
\(\Leftrightarrow x=95\)
Vậy ...
b/ \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ..
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
a)
(x-35)-120=0
=>x-35=0+120
=>x-35=120
=>x=120-35
=>x=85
b)
124+(118-x)=217
=>118-x=217-124
=>118-x=93
=>x=118-93
=>x=25
c) 125-(x+61)=82
=>x+61=125-82
=>x+61=43
=>x= 43-61
=>x= -18
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 156 - (x + 61) = 82
x + 61 = 156 - 82 = 74
x = 74 - 61 = 13
b) 5(x + 35) = 515
x + 35 = 515 : 5 = 103
x = 103 - 35 = 68
c) x : 5 = x : 6
\(\frac{x}{5}-\frac{x}{6}=0\)
\(\frac{6x-5x}{30}=0\)=> x = 0
d) (x - 42)(x - 21) = 0
=> x - 42 = 0 hoặc x - 21 = 0 => x = 42 hoặc x = 21
e) 124 + (118 - x) = 2
118 - x = 2 - 124 = -122
x = 118 - (- 122) = 240
![](https://rs.olm.vn/images/avt/0.png?1311)
\(71-\left(33+x\right)=26\)
<=> \(71-33-x=26\)
<=> \(38-x=26\)
<=> \(x=38-26=12\)
\(3636:\left(12x-91\right)=36\)
<=> \(12x-91=101\)
<=> \(12x=192\)
<=> \(x=16\)
\(\left(x-15\right)-218=0\)
<=> \(x-15=218\)
<=> \(x=233\)
\(45+\left(x-6\right).3=81\)
<=> \(\left(x-6\right).3=36\)
<=> \(x-6=12\)
<=> \(x=18\)
\(124x-4x-70x=150\)
<=> \(\left(124-4-70\right).x=150\)
<=> \(50x=150\)
<=> \(x=3\)
1) 71 - ( 33 + x ) = 26
<=> 33 + x = 71 - 26
<=> 33 + x = 45
<=> x = 12
2) 3636 : ( 12x - 91 ) = 36
<=> 12x - 91 = 101
<=> 12x = 192
<=> x = 16
3) ( x - 15 ) - 218 = 0
<=> x - 15 = 218
<=> x = 218 + 15
<=> x = 233
4) 45 + ( x - 6 ) .3 = 81
<=> 45 + ( x - 6 ) = 27
<=> x - 6 = -18
<=> x = -12
5) 124x - 4x - 70x = 150
<=> 5x = 150
<=> x = 150 : 50
<=> x = 3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\Rightarrow x-15=85\Rightarrow x=100\\ b,\Rightarrow448-x=217-124=93\\ \Rightarrow x=448-93=355\\ c,\Rightarrow x-305=804-712=92\Rightarrow x=92+305=397\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1/ -7264 + (1543 + 7264)
=-7264 + 1543 + 7264=1543
2/ (144 – 97) – 144
=144-97-144=-97
3/ (-145) – (18 – 145)(Vì có dấu trừ ở trước ngoặc nên p đổi dấu)
=-145-18+145=-18
4/ 111 + (-11 + 27)
=111-11+27=137
a)
\(x+79=0+121\)
\(x+79=121\)
\(x=121-79\)
\(x=42\)
b)
\(118-x=217-124\)
\(118-x=93\)
\(x=118-93\)
\(x=25\)
c)
\(x=3045:15\)
\(x=203\)
d)
\(6x=623-5\)
\(6x=618\)
\(x=618:6\)
\(x=103\)
e)
\(x-1=0:12\)
\(x-1=0\)
\(x=0+1\)
\(x=1\)
f)
0 chia cho mọi số khác 0 đều bằng 0
Vậy chỉ cần \(x-1\ne0\)
\(x\ne0+1\)
\(x\ne1\)