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\(\frac{63}{67}=\frac{630}{670}\)
Ta có : \(\frac{631}{671}=1-\frac{40}{671}\)
\(\frac{630}{670}=1-\frac{40}{670}\)
Vì \(\frac{40}{671}< \frac{40}{670}\) nên \(\frac{631}{671}>\frac{63}{67}\)
Ta có:
\(\frac{631}{671}>\frac{630}{670}=\frac{63}{67}\)
Vậy \(\frac{631}{671}>\frac{63}{67}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(6x-5=631\)
\(6x=636\)
\(x=106\)
b,\(x-7=\left(-12\right)+\left(-8\right)\)
\(x-7=-20\)
\(x=-13\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)491 - ( x + 83) = 336
(x+83)=491-336
(x+83)=155
x=155-83
x=72
b)( 517 - x ) + 131 = 631
( 517 - x ) =631-131
( 517 - x ) =500
x=517-500
x=17
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -7 < 0,1,2,3,4,5,6,7<8
b)
1) 631 + [ 587 - (287+231)]
= 631 + [ 587 - 518 ]
= 631 + 69
=700
2) (-524) – [(476 + 245) - 45]
= (-524) – 476 – 245 + 45
= (-524) + (– 476) + (– 245) + 45
= (-1000) + (-200)
= -1200.
= 631 + 69
= 700
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\left(67-5759\right)+5759\\ =67-5759+5759\\ =67+\left(5759-5759\right)\\ =67+0\\ =67\)
\(b.\left(-3023\right)-\left(765-3023\right)\\ =-3023-765+3023\\ =\left(-3023+3023\right)-765\\ =0-765\\ =-765\)
\(c.631+\left[587-\left(287+231\right)\right]\\ =631+587-287-231\\ =\left(631-231\right)+\left(587-287\right)\\ =400+300\\ =700\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 6 3 1 : 6 2 1 = 6 . 6 . 6 1 : 6 . 6 1 = 6
b, 7 2 1 2 : 7 = 7 2 1 2 : 7 = 7 2 : 7 = 7
c, 2018 2 0 1 8 : 1 2018 = 2018 2 0 1 8 : 1
= 2018 2 0 : 1 = 2018 1 : 1 = 2018