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a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
a: \(\Leftrightarrow2x-2+4x+8=-12\)
=>6x+6=-12
=>6x=-18
hay x=-3
b: \(\Leftrightarrow-10x-15-12+9x=13\)
=>-x-27=13
=>-x=40
hay x=-40
c: \(\Leftrightarrow-10x+70+20-5x=-15\)
\(\Leftrightarrow-15x=-105\)
hay x=7
d: \(\Leftrightarrow8x-12-7x+14=10\)
=>x+2=10
hay x=8
e: \(\Leftrightarrow-12x-18+14x+2=2\)
=>2x-16=2
hay x=9
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
\(a,x\left(-\frac{3}{7}\right)=\frac{5}{21}\)
\(\Rightarrow x=\frac{5}{21}:\left(-\frac{3}{7}\right)\)
\(\Rightarrow x=-\frac{5}{9}\)
\(b,x:\left(-\frac{2}{5}\right)=-\frac{15}{16}\)
\(\Rightarrow x=-\frac{15}{16}.\left(-\frac{2}{5}\right)\)
\(\Rightarrow x=\frac{3}{8}\)
\(c,-\frac{4}{7}:x=-\frac{2}{5}\)
\(\Rightarrow x=-\frac{4}{7}:\left(-\frac{2}{5}\right)\)
\(\Rightarrow x=\frac{10}{7}\)
\(d,\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
\(\frac{\Rightarrow2}{3}x=\frac{3}{10}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}x=-\frac{29}{70}\)
\(\Rightarrow x=-\frac{29}{70}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{87}{140}\)
a, \(x.\left(-\frac{3}{7}\right)=\frac{5}{21}\)
\(\Rightarrow x=\frac{5}{21}:\left(-\frac{3}{7}\right)\)
\(\Rightarrow x=-\frac{5}{9}\)
b, \(x:\left(-\frac{2}{5}\right)=\left(-\frac{15}{16}\right)\)
\(\Rightarrow x=\left(-\frac{15}{16}\right).\left(-\frac{2}{5}\right)\)
\(\Rightarrow x=\frac{5}{8}\)
c, \(\left(-\frac{4}{7}\right):x=-\frac{2}{5}\)
\(x=\left(-\frac{4}{7}\right):\left(-\frac{2}{5}\right)\)
\(\Rightarrow x=\frac{10}{7}\)
d, \(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
\(\Rightarrow\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}x=-\frac{29}{70}\)
\(\Rightarrow x=-\frac{29}{70}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{87}{140}\)
e, \(\frac{3}{4}x-\frac{1}{2}=\frac{3}{7}\)
\(\Rightarrow\frac{3}{4}x=\frac{3}{7}+\frac{1}{2}\)
\(\Rightarrow\frac{3}{4}x=\frac{13}{14}\)
\(\Rightarrow x=\frac{13}{14}:\frac{3}{4}\)
\(\Rightarrow x=\frac{26}{21}\)
f, \(\frac{1}{2}x+\frac{3}{5}x=-\frac{33}{25}\)
\(\Rightarrow x\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{25}\)
\(\Rightarrow\frac{11}{10}x=-\frac{33}{25}\)
\(\Rightarrow x=-\frac{33}{25}:\frac{11}{10}\)
\(\Rightarrow x=-\frac{6}{5}\)
g, \(\left(\frac{2}{3}x-\frac{4}{9}\right)\left(\frac{1}{2}+\left(-\frac{3}{7}\right):x\right)=0\)
\(\orbr{\begin{cases}\frac{2}{3}x-\frac{4}{9}=0\\\frac{1}{2}+-\frac{3}{7}:x=0\end{cases}\Rightarrow\orbr{\begin{cases}\frac{2}{3}x=\frac{4}{9}\\-\frac{3}{7}:x=-\frac{1}{2}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{9}:\frac{2}{3}\\x=-\frac{3}{7}:-\frac{1}{2}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{2}{3}\\x=\frac{6}{7}\end{cases}}}\)
h, \(-\frac{4}{7}-\frac{5}{13}.-\frac{39}{25}+-\frac{1}{42}:-\frac{5}{6}=-\frac{4}{7}+\frac{3}{5}+\frac{1}{35}\)
\(=\frac{-20+21+1}{35}=\frac{2}{35}\)
i, \(\frac{2}{9}\left[-\frac{4}{45}:\left(\frac{1}{5}-\frac{2}{15}\right)+1\frac{2}{3}\right]--\frac{5}{27}=\frac{2}{9}\left(-\frac{4}{45}:\frac{3-2}{15}+\frac{5}{3}\right)+\frac{5}{27}\)
\(=\frac{2}{9}\left(-\frac{4}{45}.15+\frac{5}{3}\right)+\frac{5}{27}=\frac{2}{9}\left(-\frac{4}{3}+\frac{5}{3}\right)+\frac{5}{27}\)
\(=\frac{2}{9}.\frac{1}{3}+\frac{5}{27}=\frac{2}{27}+\frac{5}{27}=\frac{7}{27}\)