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![](https://rs.olm.vn/images/avt/0.png?1311)
Thứ tự giảm dần:
\(\dfrac{-1}{3};\dfrac{-7}{9};\dfrac{-5}{6};\dfrac{-5}{2}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{-9}{-5};\dfrac{-7}{-5};\dfrac{2}{5};\dfrac{4}{-5};\dfrac{18}{-5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ta có: \(\frac{-5}{6}=\frac{-10}{12};\frac{-3}{4}=\frac{-9}{12}\)
\(\frac{7}{8}=\frac{357}{408};\frac{7}{24}=\frac{119}{408};\frac{16}{17}=\frac{384}{408};\frac{2}{3}=\frac{272}{408}\)
\(\Rightarrow\frac{-10}{12}< \frac{-9}{12}< \frac{119}{408}< \frac{272}{408}< \frac{357}{408}< \frac{384}{408}\)
\(\Rightarrow\frac{-5}{6}< \frac{-3}{4}< \frac{7}{24}< \frac{2}{3}< \frac{7}{8}< \frac{16}{17}\)
b) ta có: \(\frac{205}{107}=1\frac{98}{107}>1\)\(\frac{-5}{8};\frac{7}{10};\frac{-16}{19};\frac{20}{26}=\frac{10}{13};\frac{214}{315}< 1\)
ta có: \(\frac{-5}{8}=\frac{-95}{152};\frac{-16}{19}=\frac{-128}{152}\)
\(\frac{7}{10}=\frac{5733}{8190};\frac{20}{26}=\frac{10}{13}=\frac{6300}{8190};\frac{214}{315}=\frac{5564}{8190}\)
\(\Rightarrow\frac{205}{107}>\frac{6300}{8190}>\frac{5733}{8190}>\frac{5564}{8190}>\frac{-95}{152}>\frac{-128}{152}\)
=> ...
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{-8}{-3};0;\dfrac{-2}{9};\dfrac{-7}{5};\dfrac{-13}{2}\\ b,\dfrac{-13}{-6};\dfrac{-18}{-24};\dfrac{17}{30}\dfrac{-2}{5};\dfrac{-11}{20};\dfrac{-7}{12}\)