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a) 72.5–(2x+1)=630:972.5–(2x+1)=630:9
⇒245–2x–1=70⇒245–2x–1=70
⇒−2x=−22+70⇒−2x=−22+70
⇒−2x=−174⇒−2x=−174
⇒x=87⇒x=87
b)(10−4x)+120:23=17
10−4x+15=17
10−4x=17−15
10−4x=2
4x=10−2
4x=8
x=8:4
x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 72,5 - (2x + 1) = 630 : 9
⇒ 72,5 - (2x + 1) = 70
⇒ 2x + 1 = 2,5
⇒ 2x = 1,5
⇒ x = 0,75
b) (10 - 4x) + 120 : 23 = 17
⇒ (10 - 4x) + 120 : 8 = 17
⇒ (10 - 4x) + 15 = 17
⇒ 10 - 4x = 2
⇒ 4x = 8
⇒ x = 2
Vậy x = 2
a) 7^2.5-(2x+1)=630:9
b) (10-4x)+120:2^3=17
c) [124-(20-4X)]:30+7=11
d) |2x-5|=1
nhớ ghi đầy đủ bước nhá
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a\)\(.\)\(7^2.5-\left(2x+1\right)=630:9\)
\(49.5-\left(2x+1\right)=70\)
\(245-\left(2x+1\right)=70\)
\(2x+1=245-70\)
\(2x+1=175\)
\(2x=175-1\)
\(2x=174\)
\(x=174:2\)
\(x=87\)
Vậy \(x=87\)
\(b.\)\(\left(10-4x\right)+120:2^3=17\)
\(\left(10-4x\right)+120:8=17\)
\(\left(10-4x\right)+15=17\)
\(10-4x=17-15\)
\(10-4x=2\)
\(4x=10-2\)
\(4x=8\)
\(x=8:4\)
\(x=2\)
Vậy \(x=2\)
\(c.\)\(\left[124-\left(20-4x\right)\right]:30+7=11\)
\(\left[124-\left(20-4x\right)\right]:30=11-7\)
\(\left[124-\left(20-4x\right)\right]:30=4\)
\(\left[124-\left(20-4x\right)\right]=4.30\)
\(\left[124-\left(20-4x\right)\right]=120\)
\(124-20+4x=120\)
\(104+4x=120\)
\(4x=120-104\)
\(4x=16\)
\(x=16:4\)
\(x=4\)
Vậy \(x=4\)
\(d.\)\(\left|2x+5\right|=1\)
\(\Rightarrow2x+5\in\left\{-1;1\right\}\)
\(\Rightarrow2x\in\left\{-6;-4\right\}\)
\(\Rightarrow x\in\left\{-3;-2\right\}\)
Vậy \(x\in\left\{-3;-2\right\}\)
học tốt
a) \(7^2\cdot5-\left(2x+1\right)=630:9\)
\(\Leftrightarrow49\cdot5-2x-1=70\)
\(\Leftrightarrow244-2x=70\)
\(\Leftrightarrow2x=244-70\)
\(\Leftrightarrow2x=174\)
\(\Leftrightarrow x=87\)
Vậy x=87.
b) \(\left(10-4x\right)+120:2^3=17\)
\(\Leftrightarrow10-4x+120:8=17\)
\(\Leftrightarrow10-4x+15=17\)
\(\Leftrightarrow25-4x=17\)
\(\Leftrightarrow4x=25-17=8\)
\(\Leftrightarrow x=2\)
Vậy x=2
c)\([124-\left(20-4x\right)]:30+7=11\)
\(\Leftrightarrow\left(124-20+4x\right):30=4\)
\(\Leftrightarrow104+4x=120\)
\(\Leftrightarrow4x=120-104=16\)
\(\Leftrightarrow x=4\)
Vậy x=4
d) \(|2x-5|=1\)
\(\Leftrightarrow\orbr{\begin{cases}2x-5=1\\2x-5=-1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=6\\2x=4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=2\end{cases}}\)
Vậy \(x\in\text{ }\left\{3;2\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)120-3(x+4)=23
=>3(x+4)=120-23
=>3(x+4)=97
=>x+4=97:3
=>x+4=\(\frac{97}{3}\)
=>x=\(\frac{97}{3}\)-4
=>x=\(\frac{85}{3}\)
Vậy x=\(\frac{85}{3}\)
b)[(4x+28).3+55]:5=35
=>(4x+28).3+55=35.5
=>(4x+28).3+55=175
=>(4x+28).3=175-55
=>(4x+28).3=120
=>4x+28=120:3
=>4x+28=40
=>4x=40-28
=>4x=12
=>x=12:4
=>x=3
Vậyx= 3
c)\((12x-4^3).8^3=4.8^4\)
=>\(12x-64=4.8^4:8^3\)
=>12x-64=4.8
=>12x-64=32
=>12x=96
=>x=96:12
=>x=8
Vậy x=8
d)720:[41-(2x-5)]=23.5
=>720:[41-2x-5)]=40
=>41-(2x-5)=720:40
=>41-(2x-5)=18
=>2x-5=41-18
=>2x-5=23
=>2x=23+5
=>2x=28
=>x=28:;2
=>x=14
Vậy x=14
a, 120 - 3 [ x+4]=23
3 [x+4]= 120-23 = 97
3x = 97-4
3x= 93
x= 93:3
x=31
em bt làm mỗi bài này thui mà ko bt đúng ko
![](https://rs.olm.vn/images/avt/0.png?1311)
72 x 5-(2x+1)=630:9
<=> 49 x 5-2x-1=70
<=> 245-2x-1=70
<=> -2x+244=70
<=> -2x=-174
<=> x=87
tìm x biết:
a, 72.5-(2x+1)=630:9
49.5-(2x+1)=70
245-(2x+1)=70
2x+1=245-70
2x+1=175
2x=175-1
2x=174
x=174:2
x=87
Vậy x=87
b, (10-4x)+120:23=17
(10-4x)+120:8=17
(10-4x)+15=17
10-4x=17-15
10-4x=2
4x=10-2
4x=8
x=8:4
x=2
Vậy x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
ok fine
Bn có bt đọc chữ ko