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a) 115 + 5 ( x – 4 ) = 120
5 ( x – 4 ) = 120 – 115
5 ( x – 4 ) = 5
x – 4 = 5 : 5
x – 4 = 1
x = 1 + 4
x = 5
b) 5|x| – 10 0 = 3 7 : 3 5
5| x | – 1 = 3 2
5| x | = 9 + 1
5| x | = 10
| x | = 2
x = 2 hoặc x = -2
c) 2 2016 . 2 x - 1 = 2 2015
2 x - 1 = 2 2015 : 2 2016
2 x - 1 = 2 2015 - 2016
2 x - 1 = 2 - 1
⇒ x – 1 = -1
x = -1 + 1
x = 0
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Ta có:
\(115+5\left(x-4\right)=120\)
\(5\left(x-4\right)=120-115=5\)
\(\Rightarrow x-4=1\Rightarrow x=5\)
115+5(x-4)=120
5(x-4)=120-115
5(x-4)=5
x-4=5:5
x-4=1
x =1+4
x =5
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Bài 2:
a: 4x+320=480
=>4x=160
hay x=40
b: 150-x:7=120
=>x:7=30
hay x=210
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`@` `\text {Ans}`
`\downarrow`
`a)`
\(24 \div a+24=30\)
`=> 24 \div a = 30 - 24`
`=> 24 \div a = 6`
`=> a = 24 \div 6`
`=> a = 4`
Vậy, `a=4`
`b)`
\( 1974 \div 14+a \times 141=423\)
`=> 141 + a \times 141 = 423`
`=> a \times 141 = 423 - 141`
`=> a \times 141 = 282`
`=> a = 282 \div 141`
`=> a = 2`
Vậy, `a=2`
`c)`
\(120-(45-a \times 4)=115\)
`=> 45 - a \times 4 = 120 - 115`
`=> 45 - a \times 4 = 5`
`=> a \times 4 = 45 - 5`
`=> a \times 4 = 40`
`=> a = 40 \div 4`
`=> a = 10`
Vậy, `a=10`
`d)`
\((a \times 4-44) \div 4=44\)
`=> a \times 4 - 44 = 44 \times 4`
`=> a \times 4 - 44 = 176`
`=> a \times 4 = 176 + 44`
`=> a \times 4 = 220`
`=> a = 220 \div 4`
`=> a = 55`
Vậy, `a = 55.`
a) 24:a+24=30
24:a= 30 - 24
24:a=6
a= 24:6
a=4
______
b) 1974:14+ax141=423
141 + a x 141 = 423
141 x (a+1) = 423
a+1 = 423 : 141
a+1=3
a=3-1
a=2
_____
c) 120-(45-ax4)=115
45 - a x 4= 120 - 115
45 - a x 4= 5
a x 4 = 45 - 5
a x 4 = 40
a = 40:4
a=10
______
d) (ax4-44):4=44
a x 4 - 44 = 44 x 4
a x 4 - 44 = 176
a x 4 = 176 + 44
a x 4 = 220
a= 220:4
a=55
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Đáp án cần chọn là: B
2 x − 3 4 − 4 15 − 1 4 = 1 20 − 1 15 2 x − 3 4 − 1 60 = − 1 60 2 x − 3 4 = 0 2 x − 3 4 = 0 2 x = 3 4 x = 3 8
Vậy có 1 giá trị của x thỏa mãn bài toán.
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a) 7(2x-1)=(346.124)-346
14x-7=42558
14x=42551
x=42551/14
b) 4/3+2(5+7x)=23
2(5+7x)=65/3
5+7x=65/6
7x=35/6
x=5/6
a) 346.124-7.(2x-1)=343
346.124-14x+7=343
42904-14x+7=343
-14x=343-42904-7
-14x=-42568
x=\(\dfrac{-42568}{-14}\)=\(\dfrac{42568}{14}\)=3,04
vậy x = 3,04
b)\(\dfrac{4}{3}\)+2(5+7x)=115:5
\(\dfrac{4}{3}\)+10+14x=23
14x=23-10-\(\dfrac{4}{3}\)
14x= \(\dfrac{35}{3}\)
x=\(\dfrac{35}{3}\):14
x=\(\dfrac{35}{42}\)=\(\dfrac{5}{6}\)
a) 115 + 5 ( x – 4 ) = 120
5 ( x – 4 ) = 120 – 115
5 ( x – 4 ) = 5
x – 4 = 5 : 5
x – 4 = 1
x = 1 + 4
x = 5