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a)\(\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}-2\)
\(=\dfrac{144}{90}+\dfrac{105}{6}+\dfrac{50}{90}-\dfrac{180}{90}=\dfrac{119}{90}\)
b) \(3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}\)
\(=3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}\)
\(=\dfrac{54}{18}-\dfrac{15}{18}-\dfrac{8}{18}+\dfrac{24}{18}=\dfrac{55}{18}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}+2\)
\(\text{=}\dfrac{144}{90}+\dfrac{105}{90}+\dfrac{50}{90}+\dfrac{180}{90}\)
\(\text{=}\dfrac{144+105+50+180}{90}\)
\(\text{=}\dfrac{497}{90}\)
\(b)3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}\)
\(\text{=}3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}\)
\(\text{=}\dfrac{54-15-8+24}{48}\text{=}\dfrac{55}{48}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
tính phân số
a)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
b)\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{-13}{9}=1\frac{29}{90}\)
\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{16}{9}\)
\(=\frac{7}{18}\)
Đây là chj tính nhẩm, còn em muốn giải chi tiết thì quy đồng lên để giải nha.
\(a,\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{5}{9}-2\)
\(=\frac{299}{90}-2\)
\(=\frac{119}{90}\)
\(b,3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{31}{18}+\frac{32}{24}\)
\(=\frac{55}{18}\)
\(\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}-2=\dfrac{144}{90}+\dfrac{105}{90}+\dfrac{50}{90}-\dfrac{180}{90}=\dfrac{119}{90}\)
\(3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}=3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}=\dfrac{54}{18}-\dfrac{15}{18}-\dfrac{8}{18}+\dfrac{24}{18}=\dfrac{55}{18}\)
8/5+7/6+5/9-2=83/30+5/9-2
=299/90-2
=119/90
3-5/6-4/9+32/24=13/6-4/9+32/24
=13/18+32/24
=55/18