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\(\frac{8}{35}+\frac{8}{63}+\frac{8}{99}+...+\frac{8}{575}\)
= \(4x\left(\frac{2}{3x5}+\frac{2}{5x7}+\frac{2}{7x9}+...+\frac{2}{23x25}\right)\)
= \(4x\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{23}-\frac{1}{25}\right)\)
=\(4x\left(\frac{1}{3}-\frac{1}{25}\right)\)
= \(4x\frac{22}{75}\)
=\(\frac{88}{75}\)
=\(4.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{23.25}\right)\)
=\(4.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{23}-\frac{1}{25}\right)\)
=\(4.\left(\frac{1}{5}-\frac{1}{25}\right)\)
=\(4.\frac{22}{75}\)
=\(\frac{88}{75}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
A)429678
B)KHÔNG TÍNH ĐC BẠN NHÉ!
C)6638,71
D)58,7
E)748
H)21
TÌM X
a)x=3,5
b)13,6
c)19,585
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\(\dfrac{56}{35}\times\dfrac{63}{36}\times\dfrac{6}{9}\times\dfrac{5}{8}=\dfrac{8}{5}\times\dfrac{7}{4}\times\dfrac{2}{3}\times\dfrac{5}{8}=\left(\dfrac{8}{5}\times\dfrac{5}{8}\right)\times\left(\dfrac{7}{4}\times\dfrac{2}{3}\right)=1\times\dfrac{7}{6}=\dfrac{7}{6}\)
\(\dfrac{56}{35}\times\dfrac{63}{36}\times\dfrac{6}{9}\times\dfrac{5}{8}=\dfrac{8}{5}\times\dfrac{7}{4}\times\dfrac{2}{3}\times\dfrac{5}{8}=\left(\dfrac{8}{5}\times\dfrac{5}{8}\right)\times\left(\dfrac{7}{4}\times\dfrac{2}{3}\right)=1\times\dfrac{7}{6}=\dfrac{7}{6}\)
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1+2+3+4+5+6+7+8+9+...........+99=X+1+2+3+4+5+6+7+8+9+.................+99
4950=4950+X
X=4950-4950
X=0
\(\frac{8}{3}+\frac{8}{15}+\frac{8}{35}+\frac{8}{63}+\frac{8}{99}\)
\(=8.\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\)
\(=8.\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)\)
\(=8.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(=8.\left(1-\frac{1}{11}\right)\)
\(=8.\frac{10}{11}\)
\(=\frac{80}{11}\)
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