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19 tháng 8 2020

        \(\frac{7}{13}×\frac{5}{14}×\frac{39}{15}\)

\(=\frac{7×5×39}{13×14×15}\)

\(=\frac{7×5×13×3}{13×7×2×5×3}\)

\(=\frac{1}{2}\)

\(\frac{7}{13}×\frac{5}{14}×\frac{39}{15}\)

\(=\frac{7×5×39}{13×14×15}\)

\(=\frac{7×5×3×13}{13×2×7×3×5}\)

\(=\frac{1}{2}\)

15 tháng 8 2021

\(\dfrac{7}{13}\times\dfrac{5}{14}\times\dfrac{39}{15}=\dfrac{7\times5\times3\times13}{13\times7\times2\times5\times3}=\dfrac{1}{2}\)

\(\dfrac{7}{13}\cdot\dfrac{5}{14}\cdot\dfrac{39}{15}=\dfrac{1}{2}\)

`#3107`

`7/13 \div x = 14/39`

`=> x = 7/13 \div 14/39`

`=> x = 3/2`

Vậy, `x = 3/2`

________

`x \times 3/5 = 14/15`

`=> x = 14/15 \div 3/5`

`=> x = 14/9`

Vậy, `x=14/9.`

24 tháng 9 2023

\(\dfrac{7}{13}:x=\dfrac{14}{39}\)

\(x=\dfrac{7}{13}:\dfrac{14}{39}\)

\(x=\dfrac{7}{13}\times\dfrac{39}{14}\)

\(x=\dfrac{3}{2}\)

___

\(x\times\dfrac{3}{5}=\dfrac{14}{15}\)

\(x=\dfrac{14}{15}:\dfrac{3}{5}\)

\(x=\dfrac{14}{15}\times\dfrac{5}{3}\)

\(x=\dfrac{14}{9}\)

21 tháng 7 2017

\(\frac{7}{13}\cdot\frac{5}{14}\cdot\frac{39}{15}\)

Theo đề bài ta có :

\(\Leftrightarrow\frac{7.5.39}{13.14.15}\Leftrightarrow\frac{1.1.3}{1.2.3}\Leftrightarrow\frac{3}{6}\Leftrightarrow\frac{1}{2}\)

:)  :)  :)  :)

21 tháng 7 2017

\(\frac{7}{13}.\frac{5}{14}.\frac{39}{15}=\frac{7.5.3.13}{13.2.7.3.5}=\frac{1}{2}\)

a)<=>2/7:(13/24+5/24)   b)<=>15/24-9/24-4/24       c)=7.5.39/13.14.15

<=>2/7:3/4                        <=>2/24=1/12                      =3/2.3

<=>2/7x4/3                                                                    =1/2

<=>8/21                                     

4 tháng 8 2019

a. \(\frac{2}{7}:\frac{13}{24}+\frac{2}{7}:\frac{5}{24}\)

\(\frac{2}{7}:\left(\frac{13}{24}+\frac{5}{24}\right)\)

\(\frac{2}{7}:\frac{3}{4}\)

\(\frac{8}{21}\)

b. \(\frac{15}{24}-\frac{3}{8}-\frac{1}{6}\)

\(\frac{15}{24}-\frac{9}{24}-\frac{4}{24}\)

\(\frac{2}{24}=\frac{1}{12}\)

c. \(\frac{7}{13}.\frac{5}{14}.\frac{39}{15}\)

\(\frac{7.5.3.13}{13.2.7.3.5}\)

\(\frac{1}{2}\)

27 tháng 1 2016

* 100 là cái gì vậy .nhân à

6 tháng 12 2020

79600 nha

13 tháng 8 2018

a,x=9/10

b,x=16/3

c,1/7

d,1205/741

e,313/175

13 tháng 8 2018

bạn ơi bạn bị sai mất 2 câu cuối rồi đó làm ơn tính lại giùm mình nha

10 tháng 8 2022

 

1.3.77−1​+3.7.99−3​+7.9.1313−7​+9.13.1515−9​+\frac{19-13}{13.15.19}+13.15.1919−13​

=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31​−3.71​+3.71​−7.91​+7.91​−9.131​+9.131​−13.151​+13.151​−15.191​

=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31​−15.191​=28595​−2851​=28594​

b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61​.(1.3.76​+3.7.96​+7.9.136​+9.13.156​+13.15.196​)

làm giống như trên

c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81​.(1.2.31​+2.3.41​+3.4.51​+...+48.49.501​)

=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161​.(1.2.32​+2.3.42​+3.4.52​+...+48.49.502​)

=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161​.(1.2.33−1​+2.3.44−2​+3.4.55−3​+...+48.49.5050−48​)

=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161​.(1.21​−2.31​+2.31​−3.41​+3.41​−4.51​+...+48.491​−49.501​)

=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161​.(21​−24501​)=161​.(24501225​−24501​)=4900153​

d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75​.(1.5.87​+5.8.127​+8.12.157​+...+33.36.407​)

=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75​.(1.5.88−1​+5.8.1212−5​+8.12.1515−8​+...+33.36.4040−33​)

=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75​.(1.51​−5.81​+5.81​−8.121​+8.121​−12.151​+...+33.361​−36.401​)

=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75​.(51​−14401​)=75​.(1440288​−14401​)=28841​

P/S: . là nhân nha

20 tháng 8 2017

\(a,=\frac{7-1}{1.3.7}+\frac{9-3}{3.7.9}+\frac{13-7}{7.9.13}+\frac{15-9}{9.13.15}\)\(+\frac{19-13}{13.15.19}\)

\(=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}\)

\(=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}\)

\(b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)\)

làm giống như trên

\(c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)\)

\(=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)\)

\(=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)\)

\(=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)

\(=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}\)

\(d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)\)

\(=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)\)

\(=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)\)

\(=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}\)

P/S: . là nhân nha

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