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\(\frac{1}{3}.x+650\%x-x=-6\)
\(x.\left(\frac{1}{3}+650\%-1\right)=-6\)
\(\frac{35}{6}.x=-6\)
\(x=-6:\frac{35}{6}\)
\(x=-\frac{36}{35}\)
~ Thiên Mã ~
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{3}x+650\%x-x=-6\)
\(\frac{1}{3}x+\frac{13}{2}x-x=-6\)
\(x\left(\frac{1}{3}+\frac{13}{2}-1\right)=-6\)
\(x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=-6\)
\(x\frac{35}{6}=-6\)
\(x=-6.\frac{35}{6}\)
\(x=-35\)
\(\Rightarrow x=-35\)
\(\frac{1}{3}x+650\%\cdot x-x=\left(-6\right)\)
\(\Rightarrow\frac{1}{3}x+6,5\cdot x-x=\left(-6\right)\)
\(\Rightarrow x\left(\frac{1}{3}+6,5-1\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{1}{3}+\frac{13}{2}-1\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{2+39-6}{6}\right)=\left(-6\right)\)
\(\Rightarrow x\cdot\frac{35}{6}=\left(-6\right)\)
\(\Rightarrow x=\left(-6\right):\frac{35}{6}\)
\(\Rightarrow x=-\frac{36}{35}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5x + 5x+3 = 630 (5x + 5x+3 = 650 là sai nhang bạn)
=> 5x . (1 + 53) = 630
=> 5x . 126 = 630 => 5x =5 => x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
5x + 5x +2 = 650
5x + 5x . 52 = 650
5x .( 1 +25 ) = 650
5x .26 = 650
5x = 650 / 26 =25
5x = 52
nên x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x=ƯCLN\left(430,650\right)\).
Phân tích thành tích các thừa số nguyên tố: \(430=2.5.43,650=2.5^2.13\)
Suy ra \(ƯCLN\left(430,650\right)=2.5=10\)
\(\Rightarrow x=10\).
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+650-800=10\)
\(x-150=10\)
\(x=10+150\)
\(x=160\)
Vậy \(x=160\)
x + 650 - 800 = 10
x + (- 150 ) =10
x = ( - 150 ) - 10
x = -160
cả 2 "x"luôn nhé