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a: \(4^{10}\cdot2^{30}=2^{30}\cdot2^{20}=2^{50}\)
b: \(9^{25}\cdot27^4\cdot81^2=3^{50}\cdot3^{12}\cdot3^8=3^{70}\)
c: \(25^{50}\cdot125^5=5^{100}\cdot5^{15}=5^{115}\)
d: \(64^3\cdot4^8\cdot16^4=4^9\cdot4^8\cdot4^8=4^{25}\)
e: \(2^{10}:8^3=2^{10}:2^9=2\)
\(12^7:6^7=\left(\dfrac{12}{6}\right)^7=2^7\)
f: \(5^8:25^2=5^8:5^4=5^4\)
\(4^9:64^2=4^9:4^6=4^3\)
\(2^{25}:32^4=2^{25}:2^{20}=2^5\)
\(125^3:25^4=5^9:5^8=5\)
g: 2^5*8^4
=2^5*(2^3)^4
=2^5*2^12
=2^17
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\(\left(125^3.7^5-175^5:5\right):2016^{2017}\)
= \(\left[\left(5^3\right)^3.7^5-\left(5^2.7\right)^5:5\right]:2016^{2017}\)
= \(\left[5^{3.3}.7^5-5^{2.5}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^{10}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^9.7^5\right]:2016^{2017}\)
= \(0:2016^{2017}\)
= \(0\)
\(\dfrac{125^3\cdot7^5-175^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^{10}\cdot7^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^9\cdot7^5}{2016^{2017}}\)
=0
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Tích (–16) . 1253 . (–8) . (–4) . (–3) có bốn thừa số nguyên âm.
Do đó tích mang dấu dương.
Hay (–16) . 1253 . (–8) . (–4) . (–3) > 0
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(-16).1253.(-8).(-4)(-3)>0 (vì tích này là số dương)
13.(-24)(-15)(-8).4<0 (vì tích này là số âm)
câu hỏi???
`5^12 .25^4 .125^3 .625^2=5^12 . (5^2)^4 . (5^3)^3 . (5^4)^2 =5^12 .5^8 .5^9 .5^8=5^37`