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a) \(3^x-27.3^5.3^2=0\)
\(3^x-3^3.3^5.3^3=0\)
\(3^x=3^{13}\)
\(x=13\)
b) \(\left(-5+3x\right):4=16\)
\(-5+3x=64\)
\(3x=69\)
\(x=23\)
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a)
5.(12-x)-20=30
⇒60-5x-20=30
⇒-5x=30+20-60
⇒-5x=-10
⇒x=2
b)(17x - 25 ) : 8 + 65 = 92
(17x - 25 ) : 8 + 65 = 81
17x - 25 = 16 x 8 = 128
17x = 128+25=153
x= 153:17 =9
c)
x=23
Giải thích các bước giải:
3x – 10 = 2x + 13
3x-2x=13+10
x=23
d)4(2x+7)-3(3x-2)=24
4.2x+4.7-3.3x+3.2=24
8x+28-9x+6=24
8x-9x=24-28-6=-10
=>(-1)x=-10
x=-10:(-1)
x=10
a. \(5\cdot\left(12-x\right)-20=30\Leftrightarrow5\left(12-x\right)=50\)
\(\Leftrightarrow12-x=50:5=10\)
\(\Leftrightarrow x=12-10=2\)
b. \(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65=16\)
\(\Leftrightarrow17x-25=16:8=2\)
\(\Leftrightarrow17x=2+25=27\Leftrightarrow x=\frac{27}{17}\)
c. \(3x-10=2x+13\)
\(\Leftrightarrow3x-2x=10+13\)
\(\Leftrightarrow x=23\)
d. \(4\cdot\left(2x+7\right)-3\cdot\left(3x-2\right)=24\)
\(\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=10\)
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1) x-2x-3x-4x-5x=-13x thay x=-8 => -13x=(-8).(-13)=104
2)(x+1)-2(x+1)-3(x+1)-4(x+1)-5(x+1)=-13(x+1) thay x=-8 => -13(x+1)=(-13).(-7)-91
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a) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
Câu tiếp theo làm tương tự nhé =))
) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -2(2x-8)+3(4-2x)=-72-5(3x-7)
<=> -4x+16+12-6x=-72-15x+35
<=> -10x+28=-37-15x
<=> -10x+28+37+15x=0
<=> 5x+65=0
<=> 5x=-65
<=> x=-13
b) 3I2x2-7I=33
<=> I2x2-7I=11
<=> \(\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}\Leftrightarrow\orbr{\begin{cases}2x^2=18\\2x^2=-3\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=9\\x^2=\frac{-3}{2}\left(ktm\right)\end{cases}\Leftrightarrow}x=\pm3}\)
\(a,-2.\left(2x-8\right)+3.\left(4-2x\right)=-72-5\left(3x-7\right)\)
\(< =>-4x+16+12-6x=-72-15x+35\)
\(< =>-10x+15x=-72+35-16-12=-65\)
\(< =>5x=-65< =>x=\frac{-65}{5}=-12\)
\(b,3.\left|2x^2-7\right|=33\)
\(< =>\left|2x^2-7\right|=\frac{33}{3}=11\)
\(< =>\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}}\)
\(< =>\orbr{\begin{cases}2x^2=11+7=18\\2x^2=-11+7=-4\end{cases}}\)
\(< =>\orbr{\begin{cases}x^2=9\\x^2=-2\end{cases}< =>\orbr{\begin{cases}x=3or-3\\x=\varnothing\end{cases}}}\)
5(3x + 8 ) - 7(2x + 3) = 16
5.3x + 5.8 - (7.2x + 7.3) = 16
15x + 40 - 7.2x - 7.3 = 16
15x + 40 - 14x - 21 = 16
(15x - 14x) + (40 - 21) = 16
15x - 14x + 19 = 16
15x - 14x = 16 - 19
x(15 - 14) = 16 - 19
x = 16 - 19
x = -3