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\(2,5x+9=3,75x-13,5\)
\(\Rightarrow3,75x-2,5x=9+13,5\)
\(\Rightarrow1,25x=22,5\)
\(\Rightarrow x=18\)
Bài làm:
Ta có: \(x.2,5+9=x.3,75-13,5\)
\(\Leftrightarrow\frac{5}{2}x+9=\frac{15}{4}x-13,5\)
\(\Leftrightarrow\frac{15}{4}x-\frac{5}{2}x=13,5+9\)
\(\Leftrightarrow\frac{5}{4}x=\frac{45}{2}\)
\(\Leftrightarrow x=\frac{45}{2}\div\frac{5}{4}\)
\(\Rightarrow x=18\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mấy cái này dễ mà bn
a)Đặt \(A=\left|3,75-x\right|+2,5\)
Vì \(\left|3,75-x\right|\ge0\)
\(\Rightarrow\left|3,75-x\right|+2,5\ge2,5\)
Dấu = xảy ra khi 3,75 - x =0 ; x= 3,75
Vậy Min A = 2,5 khi x= 3,75
a) giá trị nhỏ nhất là2,5
b)giá trị nhỏ nhất là 2,25
c)giá trị nhỏ nhất là 0
nếu thấy đúng k cho mình nhé
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![](https://rs.olm.vn/images/avt/0.png?1311)
1) \(A=\left|-3,75\right|-\frac{31}{2}+\frac{1}{4}\)
\(A=\frac{15}{4}-\frac{31}{2}+\frac{1}{4}\)
\(A=\left(-\frac{47}{4}\right)+\frac{1}{4}\)
\(A=-\frac{23}{2}.\)
2) \(A=\frac{3}{2}-\left(-3\right)-\left(2,5-3\right)-\left[1,5+\left(-2,5\right)\right]\)
\(A=\frac{3}{2}-\left(-3\right)-\left(-\frac{1}{2}\right)-\left(-1\right)\)
\(A=\frac{9}{2}-\left(-\frac{1}{2}\right)-\left(-1\right)\)
\(A=5-\left(-1\right)\)
\(A=6.\)
Chúc bạn học tốt!
1) \(A=\left|-3.75\right|-\frac{31}{2}+\frac{1}{4}\)
\(\Leftrightarrow A=3.75-\frac{62}{4}+\frac{1}{4}\)
\(\Leftrightarrow A=\frac{15}{4}-\frac{62}{4}+\frac{1}{4}\)
\(\Leftrightarrow A=\frac{15-62+1}{4}\)
\(\Leftrightarrow A=-\frac{46}{4}=-\frac{23}{2}\)
Vậy : \(A=-\frac{23}{2}\)
2) \(A=\frac{3}{2}-\left(-3\right)-\left(2,5-3\right)-\left[1,5+\left(-2,5\right)\right]\)
\(\Leftrightarrow A=\frac{3}{2}+3-\left(-0,5\right)-\left(-1\right)\)
\(\Leftrightarrow A=1,5+3+0,5+1\)
\(\Leftrightarrow A=6\)
Vậy : \(A=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\dfrac{\left(\dfrac{35721}{4}\right)\cdot2.5^6}{\left(-\dfrac{15}{4}\right)^5}=\dfrac{3^6\cdot7^2}{4}\cdot\dfrac{5^6}{2^6}:\dfrac{-3^5\cdot5^5}{2^{10}}\)
\(=\dfrac{3^6\cdot7^2\cdot5^6}{2^8}\cdot\dfrac{2^{10}}{-3^5\cdot5^5}=-2^2\cdot3\cdot5\cdot7^2=-2940\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left|2,5-x\right|-1,3=0\)
th1: \(2,5-x\ge0\Leftrightarrow x\le2,5\)
\(\Rightarrow\left|2,5-x\right|-1,3=0\Leftrightarrow2,5-x-1,3=0\Leftrightarrow x=1,2\left(tmđk\right)\)
th2: \(2,5-x< 0\Leftrightarrow x>2,5\)
\(\Rightarrow\left|2,5-x\right|-1,3=0\Leftrightarrow x-2,5-1,3=0\Leftrightarrow x=3,8\left(tmđk\right)\)
vậy \(x=1,2;x=3,8\)
b) \(1,6.\left|x-0,2\right|=0\Leftrightarrow\left|x-0,2\right|=0\Leftrightarrow x-0,2=0\Leftrightarrow x=0,2\) vậy \(x=0,2\)
c) \(\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\)
th1: \(\dfrac{1}{3}-x\ge0\Leftrightarrow x\le\dfrac{1}{3}\)
\(\Rightarrow\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\Leftrightarrow\dfrac{1}{3}-x-\dfrac{3}{7}=0\Leftrightarrow x=\dfrac{-2}{21}\left(tmđk\right)\)
th2: \(\dfrac{1}{3}-x< 0\Leftrightarrow x>\dfrac{1}{3}\)
\(\Rightarrow\left|\dfrac{1}{3}-x\right|-\left|\dfrac{-3}{7}\right|=0\Leftrightarrow x-\dfrac{1}{3}-\dfrac{3}{7}=0\Leftrightarrow x=\dfrac{16}{21}\left(tmđk\right)\)
vậy \(x=\dfrac{-2}{21};x=\dfrac{16}{21}\)
d) \(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
th1: \(x+\dfrac{4}{15}\ge0\Leftrightarrow x\ge\dfrac{-4}{15}\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\Leftrightarrow x+\dfrac{4}{15}-3,75=-2,15\)
\(\Leftrightarrow x=\dfrac{4}{3}\left(tmđk\right)\)
th2: \(x+\dfrac{4}{15}< 0\Leftrightarrow x< \dfrac{-4}{15}\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\Leftrightarrow-x-\dfrac{4}{15}-3,75=-2,15\)
\(\Leftrightarrow x=\dfrac{-28}{15}\left(tmđk\right)\)
vậy \(x=\dfrac{4}{3};x=\dfrac{-28}{15}\)
e) ta có : \(\left|x-1,5\right|\ge0\forall x\) và \(\left|2,5-x\right|\ge0\forall x\)
\(\Rightarrow\left|x-1,5\right|+\left|2,5-x\right|=0\Leftrightarrow\left\{{}\begin{matrix}x-1,5=0\\2,5-x=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=1,5\\x=2,5\end{matrix}\right.\) 2 giá trị này khác nhau \(\Rightarrow\) phương trình vô nghiệm
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=2,5+\frac{23}{4}-\left(-3,75+\frac{1}{2}+\frac{13}{2}\right)\)
\(S=\frac{-25}{10}+\frac{23}{4}+3,75+\frac{1}{2}+\frac{13}{2}\)
\(S=\frac{-5}{2}+\frac{23}{4}+\frac{-375}{100}+\frac{1}{2}+\frac{13}{2}\)
\(S=\frac{-5}{2}+\frac{23}{4}+\frac{-15}{4}+\frac{1}{2}+\frac{13}{2}\)
\(S=\frac{-10}{4}+\frac{23}{4}+\frac{-15}{4}+\frac{2}{4}+\frac{26}{4}\)
\(S=\frac{26}{4}=\frac{13}{2}\)
\(\dfrac{3,75}{x}=\dfrac{4,8}{2,5}\)
<=> 3,75 . 2,5 = 4,8x
<=> 9,375 = 4,8x
<=> x = \(\dfrac{9,375}{4,8}=\dfrac{125}{64}\)
\(3,75:x=4,8:2,5\)
\(3,75:x=1,92\)
\(x=3,75:1,92\)
\(x\approx1,95\)