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13 tháng 4 2023

`3/7 .4/11+3/7 .7/11-2`

`= 3/7 . ( 4/11 + 7/11)-2`

`= 3/7 . 11/11 -2`

`=3/7 . 1-2`

`= 3/7-2`

`= 3/7 - 14/7`

`=-11/7`

13 tháng 4 2023

`3/7*4/11+3/7*7/11-2`

`=3/7*(4/11+7/11)-2`

`=3/7*1-2`

`=3/7-2`

`=3/7-14/7`

`=-11/7`

28 tháng 4 2017

9+3.(-5)=9+(-15)= -6

\(\frac{-2}{15}\)-\(\frac{4}{25}\)=  \(\frac{-10}{75}\)-\(\frac{12}{75}\)\(\frac{-22}{75}\)

\(\frac{-3}{5}\).  \(\frac{4}{11}\)+\(\frac{-3}{7}\).  \(\frac{7}{11}\)+   \(\frac{-3}{7}\)=  \(\frac{-12}{55}\)+  \(\frac{-21}{77}\)+   \(\frac{-3}{7}\)

                                                                    =   \(\frac{-84}{385}\)+\(\frac{-105}{385}\)+\(\frac{-165}{385}\)

                                                                    =  \(\frac{-354}{385}\)

28 tháng 4 2017

a) 9+3.(-5) =9-15=-6

b) \(\frac{-2}{15}-\frac{4}{25}=\frac{-2.5}{75}-\frac{4.3}{75}=\frac{-10-12}{75}=\frac{-22}{75}\)

c) \(\frac{-3}{5}.\frac{4}{11}+\frac{-3}{7}.\frac{7}{11}+\frac{-3}{7}=\frac{-12}{55}+\frac{-21}{77}+\frac{-3}{7}=\frac{-12.7}{385}+\frac{-21.5}{385}+\frac{-21.55}{385}=\frac{-84-105-1155}{385}=\frac{-1344}{385}=\frac{-192}{5}\)

hi! hi! hk bit dug hk :)

2:

=>27:3^x=2*25-16-31=50-47=3

=>3^x=27/3=9

=>3^x=3^2

=>x=2

1:

b: \(=16\cdot55+16\cdot45-1\)

=16(55+45)-1

=1600-1

=1599

c: \(=\dfrac{1800}{49-\left[2\cdot\left(36-34\right)^3-5\right]}\)

\(=\dfrac{1800}{49-2\cdot2^3+5}=\dfrac{1800}{49-16+5}=\dfrac{1800}{38}\)=900/19

d: \(=\dfrac{5\cdot3^{11}\cdot2^{11}-3^{11}\cdot2^{11}}{2^{10}\cdot3^{10}\cdot2^2\cdot3+7\cdot2^{12}\cdot3^{12}}\)

\(=\dfrac{3^{11}\cdot2^{11}\left(5-1\right)}{2^{12}\cdot3^{11}\left(1+7\cdot3\right)}=\dfrac{1}{2}\cdot\dfrac{4}{1+21}=\dfrac{4}{22\cdot2}=\dfrac{1}{11}\)

9 tháng 2 2017

vgcsdhvGe

25 tháng 4 2016

1971/1078

13 tháng 3 2018

=\(\frac{7.\left(2^2\right)^5.3^{10}.3+2^{10}.2^3.\left(3^2\right)^5}{2^{10}.3^{10}+2^{10}.3^{10}.2^2}\)

=\(\frac{7.2^{10}.3^{10}.3+2^{10}.2^3.3^{10}}{2^{10}.3^{10}+2^{10}.3^{10}.2^2}\)

=\(\frac{2^{10}.3^{10}\left(7.3+2^3\right)}{2^{10}.3^{10}\left(1+2^2\right)}\)

=\(\frac{7.3+2^3}{1+2^2}\)

\(\frac{7.4^5.3^{11}+2^{13}.9^5}{6^{10}+2^{12}.3^{10}}=\frac{7.\left(2^2\right)^5.3^{11}+2^{13}.\left(3^2\right)^5}{\left(2.3\right)^{10}+2^{12}.3^{10}}=\frac{7.2^{10}.3^{11}+2^{13}.3^{10}}{2^{10}.3^{10}+2^{12}.3^{10}}\)

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