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\(7^{2x}+7^{2x+3}=344\)
\(7^{2x}+7^{2x}.7^3=344\)
\(7^{2x}+7^{2x}.343=344\)
\(7^{2x}.1+7^{2x}.343=344\)
\(7^{2x}.\left(1+343\right)=344\)
\(7^{2x}.344=344\)
\(7^{2x}=344:344\)
\(7^{2x}=1\)
\(\Rightarrow7^{2x}=7^0\)
\(2x=0\)
\(x=0:2\)
\(x=0\)
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72x + 72x . 73 = 344
=> 72x.(1 + 343) = 344
=> 72x . 344 = 344
=> 72x = 344 : 344
=> 72x = 1
=> 72x = 70
=> 2x = 0
=> x= 0
72x+72x.73=344
=>72x(1+73)=344
=>72x=1
=>72x=70
=>2x=0
=>x=0
Vậy x=0.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(7^{2x}+7^{2x+3}=344\\ 7^{2x}\left(1+343\right)=344\\ 7^{2x}.344=344\\ 7^{2x}=1\\ 2x=0\\ x=0\)
Vậy x = 0
Ta có: \(7^{2x}+7^{2x+3}=344\)
\(\Leftrightarrow7^{2x}+7^{2x}\cdot7^3=344\)
\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Leftrightarrow2x=0\)
Vì 2>0
nên x=0
Vậy: x=0
![](https://rs.olm.vn/images/avt/0.png?1311)
7^x + 7^2x+3=344
7^x + 7^2x . 7^3 =344
7^x + 7^2 . 7^x . 7^3 =344
7^x . (7^2+1) . 7^3 = 344
7^x . 50 . 343 =344
làm tiếp ........
...=344-2574-344+5874=-2574+5874=3300
344-2574+(-344)+5874
= \(\left[344+\left(-334\right)\right]+\left(5874-2574\right)\)
=\(1+3300\)
=\(3300\)