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\(a,\Rightarrow\left(4x-1\right)^2=25=5^2=\left(-5\right)^2\\ \Rightarrow\left[{}\begin{matrix}4x-1=5\\4x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-1\end{matrix}\right.\\ b,\Rightarrow2^x\left(1+2^3\right)=144\\ \Rightarrow2^x=144:9=16=2^4\Rightarrow x=4\\ c,\Rightarrow3^{2x+3}=3^{2\left(x+3\right)}\\ \Rightarrow2x+3=2x+6\Rightarrow0x=3\left(vô.lí\right)\\ \Rightarrow x\in\varnothing\)
a) \(\Rightarrow x=2021-2006=15\)
b) \(\Rightarrow2x-2016=64\Rightarrow2x=2016+64=2080\Rightarrow x=1040\)
c) \(\Rightarrow\left(2x+1\right)^3=81:3=27\Rightarrow2x+1=3\)
\(\Rightarrow2x=3-1=2\Rightarrow x=1\)
Tham khảo:Tìm x thuộc N , biết:a) 2x + 2x+3 =144b) (4x -1)2 =25 x 9 - Hoc24
Bài làm:
Ta có: \(\left(2x-5\right)\left(x^3+1\right)-\left(2x-5\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left(2x-5\right)\left(x+1\right)\left(x^2-x+1\right)-\left(2x-5\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left(2x-5\right)\left(x+1\right)\left(x^2-x-1\right)=0\)
\(\Leftrightarrow x\left(x-1\right)\left(x+1\right)\left(2x-5\right)=0\)
GPT này ra ta được: \(x\in\left\{-1;0;1;\frac{5}{2}\right\}\)
\(\left(2x-5\right)\left(x^3+1\right)-\left(2x-5\right)\left(x+1\right)=0\)
\(\Leftrightarrow2x^4+2x-5x^3-5-\left(2x^2+2x-5x-5\right)=0\)
\(\Leftrightarrow2x^4+2x-5x^3-5-2x^2-2x+5x+5=0\)
\(\Leftrightarrow2x^4+5x-5x^3-2x^2=0\)
\(\Leftrightarrow x\left(2x^3+5-5x^2-2x\right)=0\)
\(\Leftrightarrow x=0;\frac{5}{2};\pm1\)
a) 2x . 4 = 128
<=> 2x = 32
<=> 2x = 25
<=> x = 5
b) x15 = x1
<=> x15 - x = 0
<=> x(x14 - 1) = 0
<=> \(\orbr{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x^{14}=1^{14}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
c) (2x + 1)3 = 125
<=> (2x + 1)3 = 53
<=> 2x + 1 = 5
<=> 2x = 4
<=> x = 2
d) (x - 5)4 = (x - 5)6
<=> (x - 5)6 - (x - 5)4 = 0
<=> (x - 5)4[(x - 5)2 - 1] = 0
<=> \(\orbr{\begin{cases}\left(x-5\right)^4=0\\\left(x-5\right)^2-1=0\end{cases}}\)
Khi (x - 5)4 = 0 => x - 5 = 0 => x = 5
Khi (x - 5)2 - 1 = 0 <=> (x - 5)2 = 12 <=> \(\orbr{\begin{cases}x-5=1\\x-5=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=4\end{cases}}\)
3) Tìm x
a) 2x = 16
=> 2x = 24
=> x = 4
Vậy x = 4
b) 2x + 3 + 2x = 144
=> 2x . 23 + 2x = 144
=> 2x . 8 + 2x = 144
=> 2x.(8 + 1) = 144
=> 2x.9 = 144
=> 2x = 144: 9
=> 2x = 16
=> 2x = 24
=> x = 4
Vậy x = 4
c) (2x + 1)3 = 8
=> (2x + 1)3 = 23
=> 2x + 1 = 2
=> 2x = 2 - 1
=> 2x = 1
=> x = 1 : 2
=> x = \(\frac{1}{2}\)
d) (x - 11)5 = 0
=> (x - 11)5 = 05
=> x - 11 = 0
=> x = 11 + 0
=> x = 11
e) x15 = x
=> x15 - x = 0
=> x.(x14 - 1) = 0
=> \(\orbr{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)
Nếu \(x^{14}-1=0\)
\(\Rightarrow x^{14}=1\)
\(\Rightarrow x^{14}=1^{14}\)
\(\Rightarrow x=\pm1\)
Vậy x = 0 ; x = 1 ; x = - 1
f) (24 - x)3 = 8
=> (24 - x)3 = 23
=> 24 - x = 2
=> x = 24 - 2
=> x = 22
Vậy x = 22
a) 2x = 16
2x = 24
x = 4. Vậy x = 4.
b) 2x+3 + 2x = 144
2x+3 + 2x = 24+3 + 24
x = 4. Vậy x = 4.
c) (2x + 1)3 = 8
(2x + 1)3 = 23
2x + 1 = 2
2x = 2 - 1
2x = 1
x = 1 : 2
x = 1/2. Vậy x = 1/2.
d) (x - 11)5 = 0
(x - 11)5 = 05
x - 11 = 0
x = 0 + 11
x = 11. Vậy x = 11.
e) x15 = x
x = 1
f) (24 - x)3 = 8
(24 - x)3 = 23
24 - x = 2
x = 24 - 2
x = 22. Vậy x = 22.