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a) x - ( - 2 ) = 6
x = 6 + ( - 2 )
x = 4
b) - x + 23 = 14 - 47
- x + 23 = -33
- x = -33 - 23
- x = -56
x = 56
a) x-(-2)=6
x+2=6
x=6-2
x=4
b)-x+23=14-47
-x+23=-33
-x=(-33)-23
-x=-56
x=56
tick cho mk nha
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a, x -(-2) =6
suy ra x + 2 =6
Suy ra x=4
b, -x + 23 = 14 -47
suy ra -x + 23 = -33
Suy ra -x = -56
suy ra x= 56
k nha ooooook
a) x-(-2)=6
x +2=6
x=6-2
x=3
b) -x+23=14-47
-x+23=-33
-x=-33-23
-x=-56
\(\Rightarrow\)x=56
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>x-3=9
=>x=12
b: =>10-x=-26
=>x=36
c: =>x:4-1=2
=>x:4=3
=>x=12
d: =>x^2=4
=>x=2 hoặc x=-2
e: =>(x-2)^2=100
=>x-2=10 hoặc x-2=-10
=>x=12 hoặc x=-8
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 10:
a: 2x-3 là bội của x+1
=>\(2x-3⋮x+1\)
=>\(2x+2-5⋮x+1\)
=>\(-5⋮x+1\)
=>\(x+1\in\left\{1;-1;5;-5\right\}\)
=>\(x\in\left\{0;-2;4;-6\right\}\)
b: x-2 là ước của 3x-2
=>\(3x-2⋮x-2\)
=>\(3x-6+4⋮x-2\)
=>\(4⋮x-2\)
=>\(x-2\inƯ\left(4\right)\)
=>\(x-2\in\left\{1;-1;2;-2;4;-4\right\}\)
=>\(x\in\left\{3;1;4;0;6;-2\right\}\)
Bài 14:
a: \(4n-5⋮2n-1\)
=>\(4n-2-3⋮2n-1\)
=>\(-3⋮2n-1\)
=>\(2n-1\inƯ\left(-3\right)\)
=>\(2n-1\in\left\{1;-1;3;-3\right\}\)
=>\(2n\in\left\{2;0;4;-2\right\}\)
=>\(n\in\left\{1;0;2;-1\right\}\)
mà n>=0
nên \(n\in\left\{1;0;2\right\}\)
b: \(n^2+3n+1⋮n+1\)
=>\(n^2+n+2n+2-1⋮n+1\)
=>\(n\left(n+1\right)+2\left(n+1\right)-1⋮n+1\)
=>\(-1⋮n+1\)
=>\(n+1\in\left\{1;-1\right\}\)
=>\(n\in\left\{0;-2\right\}\)
mà n là số tự nhiên
nên n=0
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>19/23>19/x>19/29
=>\(x\in\left\{24;25;26;27;28\right\}\)
b: =>88/132<88/x<88/128
=>132>x>128
=>\(x\in\left\{131;130;129\right\}\)
c: =>\(\left\{{}\begin{matrix}\dfrac{4}{x}-\dfrac{x}{8}< 0\\\dfrac{x}{8}-\dfrac{5}{x}< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{32-x^2}{8x}< 0\\\dfrac{x^2-40}{8x}< 0\end{matrix}\right.\)
=>32<x^2<40
=>x=6
![](https://rs.olm.vn/images/avt/0.png?1311)
b: \(\Leftrightarrow x+8\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{-7;-9;-3;-13\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
tính :
0 - ( -2 ) + 6
= 0+2+6
= 8
tìm số nguyên x , biết :
a ) x - ( -2 ) = 6
x + 2 = 6
x = 6 - 2
x = 4
b ) -x + 23 = 24 - 47
-x + 23 = -23
-x = -23 -23
-x = -46
x = 46
a ) x - ( - 2 ) = 6
x = 6 + ( - 2 )
x = 4
b ) -x + 23 = 14 - 47
-x + 23 = - 33
- x = - 33 - 23
- x = - 56
a)x-(-2)=6
x+2=6
x=6-2
x=3
b)-x+23=14-47
-x+23=-33
-x=(-33)-23
-x=-56
=>x=56
tick cho mk nha bạn Trần Ngọc Mai