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\(\left(2,8x-32\right):\frac{2}{3}=-90\\ \frac{14}{5}x-32=\left(-90\right)\cdot\frac{2}{3}\\ \frac{14}{5}x-32=-60\\ \frac{14}{5}x=\left(-60\right)+32\\ \frac{14}{5}x=-28\\ x=\left(-28\right):\frac{14}{5}\\ x=\left(-28\right)\cdot\frac{5}{14}\\ x=-10\)Vậy x = -10
\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(2,8x-32=-90.\frac{2}{3}\)
\(2,8x-32=-60\)
\(2,8x=-60+32\)
\(2,8x=-28\)
\(x=-28:2,8=-10\)
Vậy \(x=-10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2 , 8 x - 32 = -90.\(\dfrac{2}{3}\)
2 , 8 x - 32 = -60
2 , 8 x = -60 + 32
2 , 8 x = -28
x = -28 : 2, 8
x = -10
\(\left(2,8x-32\right):\dfrac{2}{3}=-90\\ \left(2,8x-32\right)=-90.\dfrac{2}{3}=-60\\ 2,8x=-60+32=-28\\ x=-28:2,8=-10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(\Rightarrow\left(2,8x-32\right)=-90\cdot\frac{2}{3}\)
\(\Rightarrow\left(2,8x-32\right)=-60\)
\(\Rightarrow2,8x=-60+32\)
\(\Rightarrow2,8x=-28\)
\(\Rightarrow x=-10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(2,8x-32=-90.\frac{2}{3}=\frac{-90.2}{3}=\frac{-30.2}{1}=-60\)
\(\frac{14}{5}x=-60+32=-28\)
\(x=-28:\frac{14}{5}=-28.\frac{5}{14}=\frac{-28.5}{14}=\frac{-2.5}{1}=-10\)
(2,8X-32):2/3=-90
2,8X -32=-90*2/3
2,8X-32=-60
2,8X=-60+32
2,8X=-28
X=-28/2,8
X=-10
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{7}{12}-\left(x+\dfrac{7}{10}\right):\dfrac{6}{5}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{10}:\dfrac{6}{5}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{12}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{5}{4}+\dfrac{7}{12}\)
\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{11}{6}\)
\(\Leftrightarrow x=\dfrac{7}{12}-\dfrac{11}{6}\)
\(\Leftrightarrow\dfrac{-5}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A/\(\left(2,8x-32\right):\frac{2}{3}=-90\)
\(\left(\frac{28}{10}x-32\right)=\frac{-90}{1}.\frac{2}{3}\)
\(\left(\frac{14}{5}x-32\right)=\frac{-30}{1}.\frac{2}{1}\)
\(\left(\frac{14}{5}x-32\right)=-60\)
\(\frac{14}{5}x=-60+32\)
\(\frac{14}{5}x=-28\)
\(x=\frac{-28}{1}:\frac{14}{5}\)
\(x=\frac{-28}{1}.\frac{5}{14}\)
\(x=\frac{-2}{1}.\frac{5}{1}=-10\)
B/\(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)
\(\left(\frac{45}{10}-2x\right).\frac{11}{7}=\frac{11}{14}\)
\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}:\frac{11}{7}\)
\(\left(\frac{9}{2}-2x\right)=\frac{11}{14}.\frac{7}{11}\)
\(\left(\frac{9}{2}-2x\right)=\frac{1}{2}.\frac{1}{1}=\frac{1}{2}\)
\(2x=\frac{9}{2}-\frac{1}{2}\)
\(2x=\frac{8}{2}\)
\(x=\frac{8}{2}:\frac{2}{1}=\frac{8}{2}.\frac{1}{2}\)
\(x=\frac{4}{2}.\frac{1}{1}=\frac{4}{2}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(\frac{1}{7}\)b,\(\frac{7}{4}\)c,\(\frac{-10}{3}\)d,ko rõ e,=10
( 2,8x - 32 ) : 2/3 = -90
( 2,8x - 32 ) = -60
2,8x = -60 +32
2,8x = -28
x = -28 : 2,8
x = -10
(2,8x - 32) : 2\3 = -90
2,8x - 32 = -90 . 2/3
2,8x - 32 = -60
2,8x = -60 + 32
2,8x = -28
x = -28 : 2,8
x = -10