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\(\left(2600+6400\right)-3.X=1200\)
\(9000-3.X=1200\)
\(3.X=9000-1200\)
\(3.X=7800\)
\(X=7800:3\)
\(X=2600\)
(2600+6400)-3xX=1200
⇒ 9000-3xX=1200
⇒ 3xX=9000-1200=7800
⇒ X=7800:3=2600
⇒ X=2600
![](https://rs.olm.vn/images/avt/0.png?1311)
( 2600+6400 ) - 3. x = 1200
9000 -3 . x = 1200
3 . x = 9000-1200
3 . x = 7800
x = 7800 : 3
x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
(2600 + 6400) – 3x = 1200
9000 – 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 7800 : 3
x = 2600
Vậy x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
a,(2600+6400)-3 .x = 1200
=> 9000-3 .x= 1200
=> 3.x= 7800
=. x=2600
b, (6.x-72):2-84= 201
(6x-72):2=285
6x-72=570
6x=642
x=107
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(2600+6400\right)-3-x=1200\)
\(\Rightarrow9000-3-x=1200\)
\(\Rightarrow3-x=9000-1200\)
\(\Rightarrow3-x=7800\)
\(\Rightarrow x=7797\)
b) \(\left[\left(6\cdot x-72\right):2-84\right]\cdot28=5628\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=5628:28\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=201\)
\(\Rightarrow\left(6\cdot x-72\right):2=201+84\)
\(\Rightarrow\left(6\cdot x-72\right):2=285\)
Đến dei bạn tự làm, ý b mình không chắc chắn lắm
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#)Giải :
\(123-5\left(x+4\right)=38\)
\(\Leftrightarrow5\left(x+4\right)=85\)
\(\Leftrightarrow x+4=17\)
\(\Leftrightarrow x=13\)
\(\left(3x-16\right)343=2.2401\)
\(\Leftrightarrow\left(3x-16\right)343=4802\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=10\)
\(\left(2600+6400\right)-3x=1200\)
\(\Leftrightarrow9000-3x=1200\)
\(\Leftrightarrow3x=7800\)
\(\Leftrightarrow x=2600\)
P/s : Câu cuối cùng lỗi chỗ b4 ph k ? hay là tìm cả b và x thế ???
\(123-5\left(x+4\right)=38\)
\(=>123-5x-20=38\)
\(=>-5x=-123+20+38\)
\(=>-5x=-65\)
\(=>x=13\)
b, \(\left(3x-16\right)343=2.2401\)
=>1029x -5488= 4802
=> 1029x=5488+4802
=> 1029x= 10290
=> x=10
c, (2600+6400)-3x=1200
=> 9000-3x=1200
=> -3x= -9000+1200
=> -3x= -7800
=> x=2600
d,
k hiểu đề
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (2600 + 6400) - 3 . x = 1200
9000 - 3.x = 1200
3x = 9000-1200
3x = 7800
x = 7800:3
x = 2600
b) câu này ko có tổng hả Công chúa nhí nhảnh? check lại giùm Nhi nha!
a) \(\left(2600+6400\right)-3x=1200\)
\(9000-3x=1200\)
\(3x=9000-1200\)
\(3x=7800\)
\(x=\frac{7800}{3}\)
\(x=2600\)
vậy \(x=2600\)
b) \(\left[\left(6x-72\right):2-84\right].28+5628=0\)
\(\left[\frac{6x}{2}-\frac{72}{2}-84\right].28+5628=0\)
\(\left[3x-36-84\right].28=-5628\)
\(3x-120=\frac{-5628}{28}\)
\(3x-120=-201\)
\(3x=-201+120\)
\(3x=-81\)
\(x=-27\)
vậy \(x=-27\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,(6400+2600)-3x=1200
9000-3x=1200
3x=9000-1200
3x=7800
x=7800:3
x=2600
b,(4x-[(8000-3567)-(2031-1598)]=400
(4x-[4433-433]=400
4x-4000=400
4x=400+4000
4x=4400
x=4400:4
x=1100
C;2448:[(119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
a. (6400+2600) -3x=1200
=> 9000-3x=1200
=> 3x=9000-1200
=> 3x=7800
=> x=7800:3
=> x=2600
b. {4x-[(8000-3567)-(2031-1598)]}=400
=> { 4x-(4433-433)}=400
=> 4x-4000=400
=> 4x=400+4000
=> 4x=4400
=> x=4400:4
=> x=1100
c. 2448:[(119-(x-6)]=24
=> 119-(x-6)=2448:24
=> 119-(x-6)=102
=> x-6=119-102
=> x-6=17
=> x=17+6
=> x=23
=>9000-3x=1200
=>3x=9000-1200
=>3x=7800
=>x=7800:3
=>x=2600
(2600+6400)-3.x=1200
=>9000-3.x=1200
=>3.x=9000-1200
=>3.x=7800
=>x=7800:3
=>x=2600