Question

[Cậu Bé Ngu Ngơ]

2014-lx-12l+(x-12)²=2013 l12-xl

Answer 1

[Akai Haruma]

Lời giải:

** Sửa đề $2014|x-12|$ thay vì $2014-|x-12|$

$2014|x-12|+(x-12)^2=2013|12-x|$

$2014|x-12|+|x-12|^2-2013|x-12|=0$

$|x-12|+|x-12|^2=0$

$|x-12|(|x-12|+1)=0$

Do $|x-12|+1\geq 1>0$ nên $|x-12|=0$

$\Rightarrow x=12$.