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=9x2^25-2^2x2^26/2^24x5^2-2^27x3
=9x2^25-2^28/2^24x5^2-2^27x3
=2^25x(9-2^3)/2^24x(5^2-2^3x3)
=2^25/2^24
=2^1=2
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Ta có: 72x-62x = 13.23-26 => x(72-62) = 13.8-26 => 13x = 78 => x = 78:13 => x = 6 Vậy, x = 6.
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2^39=2^(3.13)=(2^3)^13=8^13
3^26=3^(13.2)=(3^2)^13=9^13
8^13.9^13=72^13
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** Bổ sung điều kiện $x,y$ là các số nguyên.
$x+5y+xy=6$
$(x+xy)+5y=6$
$x(1+y)+5(y+1)=11$
$(y+1)(x+5)=11$
Vì $x,y$ nguyên nên $x+5, y+1$ cũng nguyên. Ta xét các TH sau:
TH1: $x+5=1, y+1=11\Rightarrow x=-4; y=10$
TH2: $x+5=11, y+1=1\Rightarrow x=6; y=0$
TH3: $x+5=-1; y+1=-11\Rightarrow x=-6; y=-12$
TH4: $x+5=-11; y+1=-1\Rightarrow x=-16; y=-2$
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\(\left(x-5\right)^5=\left(x-5\right)^6\)
\(\Rightarrow\left(x-5\right)^6-\left(x-5\right)^5=0\)
\(\Rightarrow\left(x-5\right)^5.\left(x-5-1\right)=0\)
\(\Rightarrow\left(x-5\right)^5.\left(x-6\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x-5\right)^5=0\\x-6=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)
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a)\(51-\left(3+x\right)=26\\ \Leftrightarrow51-3-x=26\\ \Leftrightarrow x=51-3-26\\ \Leftrightarrow x=22\)
b)Ta có:\(Ư_{\left(24\right)}=\left\{1;2;3;4;6;8;12;24\right\}\)
mà x>10⇒x=\(\left\{12;24\right\}\)
c)\(5.2^2-\left(18:3+2021^0\right)=5.4-6=20-6=14\)
\(2^x-26=6\\ \Leftrightarrow2^x=32\\ \Leftrightarrow2^x=2^5\\ \Leftrightarrow x=5\)
\(2^x-26=6\)
⇒ \(2^x=6+26=32\)
⇒ \(2^x=32=2^5\)
⇒ \(x=5\)