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![](https://rs.olm.vn/images/avt/0.png?1311)
a) ƯCLN (16, 24) = 8, ƯC (16, 24) = {1; 2; 4; 8};
b) Ta có 180 = 22 . 32 . 5; 234 = 2 . 32 . 13;
ƯCLN (180, 234) = 2 . 32 = 18, ƯC (180, 234) = {1; 2; 3; 6; 9; 18};
c) Ta có 60 = 22 . 3 . 5; 90 = 2 . 32 . 5; 135 = 33 . 5. Do đó
ƯCLN (60, 90, 135) = 3 . 5 = 15; ƯC (60, 90, 135) = {1; 3; 5; 15}.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 30=2.3.5
135=32.5
=>UTLN(30,135)=3.5=15
b)30=2.3.5
234=2.32.13
=>UTLN(30,234)=2.3=6
c)134=2.67
60=22.3.5
=>UTLN(134,60)=2
d)176=22.4.11
234=2.32.13
=>UTLN(176,234)=2
e)180=22.32.5
176=24.11
=>UTLN(180,176)=22=4
![](https://rs.olm.vn/images/avt/0.png?1311)
a)UCLN(180;234)=18
=> UC(180,234)={1;2;3;6;9;18}
b)UCLN(60;90;135)=15
=>UC(60;90;135)={1;3;5;15}
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 16=24 24=23.3
UCLN (16,24)=23=8
=> UC(16,24,)=(1,2,4,8)
Tich nha
Ta có:16=24 24=23x3
ƯCLN(16,24)=23=8
=> ƯC(16,24)=(1,2,4,8)
Ta có: 180=22x32x5 234=2x32x13
ƯCLN(180,234)=2x32=18
=> ƯC(60,90,135)=180,234)=(1,2,3,6,9,18)
Ta có:60=22x3x5 90=2x32x5 135=33x5
ƯCLN(60,90,135)=3x5=15
=> ƯC(60,90,135)=(1,3,5,15)
Đây nha bạn.
Chúc bạn học tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(180=2^2.3^2.5\)
\(234=2.3^2.13\)
\(UCLN\left(180;234\right)=2.3^2=18\)
\(UC\left(180;234\right)=\left\{1;2;3;6;9;18\right\}\) (các phần tử thuộc N)
![](https://rs.olm.vn/images/avt/0.png?1311)
16=24;24=23.3
ƯCLN(16;24) =23=8; ƯC(16;24)={1;2;3;8}
180=22.32.5;234=2.32.13
ƯCLN(180;2340) =2.32=18; ƯC(180;234)={1;2;3;6;9;18}
60=22.3.5;90=2.32.5;135=33.5
ƯCLN(60;90;135)=3.5=15; ƯC(60;90;135)={1;3;5;15}
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 16= 24
24= 23.3
\(\Rightarrow\)ƯCLN (16; 24)= 23= 8
\(\Rightarrow\)ƯC (16; 24)= Ư (8)= {1;2;4;8}
b, 180= 22.32.55
234= 2.33.13
\(\Rightarrow\)ƯCLN (180; 234)= 2.32= 18
\(\Rightarrow\)ƯC (180; 234)= Ư (18)= {1;2;3;6;9;18}
c, 60= 22.3.5
90= 32.2.5
135= 33.5
\(\Rightarrow\)ƯCLN (60;90;135)= 3.5= 15
\(\Rightarrow\)ƯC (60;90;135)= Ư (15)= {1;3;5;15}
1
ta có
180=22.32.5
234=2.32.13
vậy UCLN(180;234)=2.32=18
2
ta có
60=22.3.5
90=2.32.5
135=33.5
vậy UCLN(60;90;135)=3.5=15
3
ta có
16=24
80=24.5
176=24.11
vậy UCLN(16;80;176)=24=16
4
ta có
18=2.32
30=2.3.5
77=7.11
vậy UCLN(18;30;77)=1
18
15
16
1