Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
uses crt;
var st:string;
i,d,dem:integer;
begin
clrscr;
write('Nhap xau:'); readln(st);
d:=length(st);
dem:=0;
for i:=1 to d do
if (st[i] in ['a'..'z']) or (st[i] in ['A'..'Z']) then inc(dem);
writeln(dem);
readln;
end.
uses crt;
var st:string;
a:array[1..255]of string;
i,d,dem,kt,j,dem1:integer;
begin
clrscr;
write('Nhap xau:'); readln(st);
d:=length(st);
a[1]:=st[1];
dem:=1;
for i:=1 to d do
begin
kt:=0;
for j:=1 to dem do
if st[i]=a[j] then kt:=1;
if kt=0 then
begin
inc(dem);
a[dem]:=st[i];
end;
end;
for i:=1 to dem do
begin
dem1:=0;
for j:=1 to d do
if a[i]=st[j] then inc(dem1);
writeln(a[i],' xuat hien ',dem1,' lan');
end;
readln;
end.
uses crt;
var a:string;
c:char;
i,dem:integer;
begin
clrscr;
readln(a);
readln(c);
dem:=0;
for i:=1 to length(a) do
if a[i]=c then dem:=dem+1;
writeln(dem);
readln;
end.
Program HOC24;
var i,d1,d2: byte;
st1,st2: string[60];
begin
write('Nhap xau st1: '); readln(st1);
//---------------Câu 1-------------------
d1:=0; d2:=0;
for i:=1 to length(st1) do
begin
if st1[i]='A' then d1:=d1+1;
if st1[i]='a' then d2:=d2+1;
end;
writeln('Co ',d1,' ki tu A trong xau');
writeln('Co ',d2,' ki tu a trong xau');
//---------------------- Câu 2 --------------------
st2:='';
for i:=1 to length(st1) do if st1[i] in ['a'..'z'] then st2:=st2+st1[i];
writeln('Xau st2 la: ',st2);
//------------------------------Câu 3--------------------
for i:=1 to length(st1) do st1[i]:=upcase(st1[i]);
write('Xau st1 sau khi in hoa la: ',st1);
//--------------------------------------------------------
readln
end.
uses crt;
var s:string;
i,d:integer;
begin
clrscr;
write('Nhap xau S:'); readln(s);
d:=length(s);
for i:=1 to d do
if (s[i] in ['a'..'z']) or (s[i] in ['A'..'Z']) then delete(s,i,1);
writeln('Xau sau khi xoa het ki tu chu la: ',s);
readln;
end.
Var a: string;
i, Dem: integer;
Begin
writeln(‘nhap xau:’);
Readln(a);
Dem:=0;
For i:=1 to length(a) do
If (‘a’<=a[i]) and (a[i]<=’z’)
Dem:= Dem+1;
Writeln(Dem);
Readln
End.
Var a: string;
i, Dem: integer;
Begin
writeln(‘nhap xau:’);
Readln(a);
Dem:=0;
For i:=1 to length(a) do
If (‘A’<=a[i]) and (a[i]<=’Z’) then
Dem:= Dem+1;
Writeln(Dem);
Readln
End.
