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a: =5,3+5,1-5,3+4,9=10
b: =2,7-51,4-48,6+7,3
=10-100=-90
c: =2,5(-0,124+10,124)=2,5x10=25
d: =6,3-6,3+4.9=4,9
e: =15,3-21,5-4,5=-10,7
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1).15,3-21,5-3.1,5 = -10.7
2).2(4 2-2.4,1)+1,25:5 = 0.300370048 ( cái nài mik bấm máy ra vậy nếu sai thì bảo mik nha )
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a,
\(\begin{array}{l}15,3 - 21,5 - 3.1,5\\ = 15,3 - 21,5 - 4,5\\ = 15,3 - \left( {21,5 + 4,5} \right)\\ = 15,3 - 26\\ = - \left( {26 - 15,3} \right)\\ = - 10,7\end{array}\)
b,
\(\begin{array}{l}2.\left( {{4^2} - 2.4,1} \right) + 1,25:5\\ = 2.\left( {16 - 8,2} \right) + 0,25\\ = 2.7,8 + 0,25\\ = 15,6 + 0,25\\ = 15,85\end{array}\)
a, 15 , 3 − 21 , 5 − 3.1 , 5 = 15 , 3 − 21 , 5 − 4 , 5 = 15 , 3 − ( 21 , 5 + 4 , 5 ) = 15 , 3 − 26 = − ( 26 − 15 , 3 ) = − 10 , 7 b, 2. ( 4 2 − 2.4 , 1 ) + 1 , 25 : 5 = 2. ( 16 − 8 , 2 ) + 0 , 25 = 2.7 , 8 + 0 , 25 = 15 , 6 + 0 , 25 = 15 , 85
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=15,3*1/35,5+0,5*1/15,3+0,125
=153/355+5/153+0,125
=0,587
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\(\left(15,3-x\right)^8=\left(x-15,3\right)^7\)
\(\Rightarrow\left(x-15,3\right)^8=\left(x-15,3\right)^7\)
\(\Rightarrow\left(x-15,3\right)^8-\left(x-15,3\right)^7=0\)
\(\Rightarrow\left(x-15,3\right)^7\left(x-15,3-1\right)=0\)
\(\Rightarrow\left(x-15,3\right)\left(x-16,3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-15,3=0\\x-16,3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=15,3\\x=16,3\end{cases}}}\)
Vậy \(x\in\left\{15,3;16,3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`-x + 3,57x - 5,12x = 15,3`
`=>-1x + 3,57x - 5,12x = 15,3`
`=> (-1 + 3,57- 5,12)x=15,3`
`=> -2,55x=15,3`
`=> x= 15,3 : (-2,55)`
`=>x= -6`
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-10,7
=15,3-21,5-4,5=-10,7