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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
![](https://rs.olm.vn/images/avt/0.png?1311)
x\(^2\)-(a+b)x+ab
= x\(^2\)-ax-bx+ab
= x(x-a) - b(x-a)
= ( x-a).( x-b)
ax-2x-a\(^2\)+2a
= x(a-2) - a(a-2)
= (a-2).( x-a)
![](https://rs.olm.vn/images/avt/0.png?1311)
x2-2x-3 = x2-3x+x-3 = x(x-3) + (x-3) = (x+1)(x-3)
CHọn mình nha :)
\(x^2-2x-3\)
\(=x^2+x-3x-3\)
\(=x\left(x+1\right)-3\left(x+1\right)\)
\(=\left(x+1\right)\left(x-3\right)\)
hk tot
^^
![](https://rs.olm.vn/images/avt/0.png?1311)
=x^3-2x^2+2x-4-9
=(x-2)(x^2+2)-9
\(=\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}-3\right)\left(\sqrt{\left(x-2\right)\left(x^2+2\right)}+3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ \(=2xy+x^2-2y^2-xy=x\left(2y+x\right)-y\left(2y+x\right)=\left(x-y\right)\left(2y+x\right)\)
b/ \(=x^2-3xy-2y^2\)
c/ \(=2xy-6y^2+x^2-3xy=2y\left(x-3y\right)+x\left(x-3y\right)=\left(2y+x\right)\left(x-3y\right)\)
d/ \(=xy-2y^2+2x^2-4xy=y\left(x-2y\right)+2x\left(x-2y\right)=\left(y+2x\right)\left(x-2y\right)\)
a)(x-y)(x+2y)
b) nghiệm lẻ>mìh nghĩ là sai đề
c)(x-3y)(x+2y)
d)(x-2y)(2x+y)
____________________________
li-ke cho mk nha bnLe Ngoc Bao Chau
![](https://rs.olm.vn/images/avt/0.png?1311)
x^2 + xy - 2y^2 = ( x^2 - 2xy + y^2 ) + 3xy - 3y^2 = ( x - y )^2 + 3y.( x - y ) = ( x - y )(x + 2y)
1. =2(x2-2xy+y2-16)
=2((x-y)2-42)
=2(x-y-4)(x-y+4)
2. =5(x2-2.1/10.x+1/100-y2+2.1/10y-1/100)
=5.((X-1/10)2-(Y-1/10)2)
=5(X-1/10-Y+1/10)(X-1/10+Y-1/10)
=5(X-Y)(X+Y-2/10)