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cách làm như sau:
125.[85+(12.13+144)/15+120/4] = 125.[85+(156+144)/15+120/4] = 125.(85+300/15+120/4) = 125.(85+20+30) = 125.135=16875
![](https://rs.olm.vn/images/avt/0.png?1311)
a = 125.64.50
= 8000.50= 400000
b = (-50025)
c = (-3034) - 1066
= (-4100)
d = (-54).(38+12-50)
= (-54). 50-50
= (-54).0 = 0
e = 85.8-35.58
= 680-2030=(-1350)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,5x-16=40-1\)
<=>\(5x=40-1+16\)
<=>\(5x=55\)
<=>\(x=11\)
\(b,x-10=-25\)
<=>\(x=\left(-25\right)-10\)
<=>\(x=-35\)
\(c,-12+x=-30\)
<=>\(x=\left(-30\right)+12\)
<=>\(x=-18\)
a) 5x-16=40-1
5x-16=39
5x=39+16
5x=55
x=55:5
x=11
b)x-10=(-25)
x=(-25)+10
x=(-15)
c) -12+x= -30
x= -30-(-12)
x= -30+12
x= -18
d) 2x +12 = -40+ 6
2x+12=(-34)
2x=(-34)-12
2x=(-46)
x=(-46):2
x=(-23)
e)125:(3x-13)=25
3x-13=125:25
3x-13=5
3x=5+13
3x=18
x=18:3
x=6
f)541+(218-x)=735
218-x=735-541
218-x=194
x=218-194
x= 24
g) 3(2x+1)-19=14
3(2x+1)=14+19
3(2x+1)=33
2x+1=33:3
2x+1=11
2x=11-1
2x=10
x=10:2
x=5
h)175-5(x+3)=85
5(x+3)=175-85
5(x+3)=90
x+3=90:5
x+3=18
x=18-3
x=15
i)8x+(-3)=39
8x=39-(-3)
8x=42
x=42:8
x=42/8
L)2x+4x=36+(-6)
6x=30
x=30:6
x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(125:5^x+5^2=26\)
\(\Rightarrow125:5^x+25=26\)
\(\Rightarrow125:5^x=26-25\)
\(\Rightarrow125:5^x=1\)
\(\Rightarrow5^x=125:1\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 125 : 5x = 5
=> 5x = 125 : 5 => 5x = 25
=> 5x = 52 => x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì 125 chia cho n dư 5 nên 125 – 5 ⋮ n hay 120 ⋮ n
85 chia cho n dư 1 nên 85 – 1 ⋮ n hay 84 ⋮ n
Suy ra n ∈ UC(120,84) và n>5
Có UCLN(120,84) = 12 nên n ∈ U(12) = {1;2;3;4;6;12} và n>5
Vậy n ∈ {6;12}
\(\Leftrightarrow5x=40\\ \Leftrightarrow x=8\)
x=8