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\(12,36.3,5+12,36.2,4+12,36.4,1\)
\(=12,36\left(3,5+2,4+4,1\right)\)
\(=12,36.10\)
\(=123,6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có 12,36 x 3,5 + 12,36 x 4 +12,36 x 4,1
<=> 12,36 x (4+3,5+4,1)
<=> 12,36 x 11,6 = 143,376
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\(12.64+12.36-100\)
\(=12\left(64+36\right)-100\)
\(=12.100-100\)
\(=1200-100=1100\)
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\(a.36+15+64\\ =\left(36+64\right)+15\\ =100+15\\ =115\\ b.12\cdot36+12\cdot64\\ =12\cdot\left(36+64\right)\\ =12\cdot100\\ =1200\\ c.\left(3^2+2^3\cdot5\right):7\\ =\left(9+8\cdot5\right):7\\ =\left(9+40\right):7\\ =49:7\\ =7\)\(\)
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Bài làm
1. Rút gọn
\(\frac{2^5.7+2^6}{2^5.5^2-2^5.7}=\frac{2^5\left(7+2\right)}{2^5\left(25-7\right)}=\frac{9}{18}=\frac{1}{2}\)
2. So sánh
Ta có: \(\frac{2.7+6.21+9.28}{4.9+8.27+12.36}\)
\(=\frac{14+126+252}{36+216+432}=\frac{392}{684}=\frac{98}{171}\)
Mà ta thấy, mẫu số của phân số 98/171 lớn hơn mẫu số của phân sốc 49/84 ( 171 > 84 )
=> \(\frac{98}{171}< \frac{49}{84}\)
Vậy \(\frac{2.7+6.21+9.28}{4.9+8.27+12.36}< \frac{49}{84}\)
3. Tìm x
a) ( 2x + 14 ) : 22 - 3 = 1
( 2x + 14 ) : 4 - 3 = 1
( 2x + 14 ) : 4 = 1 + 4
( 2x + 14 ) : 4 = 5
2x + 14 = 5 x 4
2x + 14 = 20
2x = 6
x = 3
Vậy x = 3
b) 32x - 5 + 2 = 29
9x - 5 + 2 = 29
9x - 5 = 27
9x = 32
x = 32 : 9 = \(\frac{32}{9}\)
Vậy x = \(\frac{32}{9}\)
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\(12,36.35,5+12,36.4+12,36.4,1\)
\(=12,36\left(3,5+4+4,1\right)\)
\(=12,36.11,6=143,376\)