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4.2\(^x\)+3.2\(^{x+1}\)=80
4.2\(^x\)+3.2\(^x\).2\(^1\)=80
2\(^x\).(4+3.2)=80
2\(^x\).10=80
2\(^x\)=8
⇒x=3 vì 2\(^3\)=8
= 22 .2X+3.2X.21=80
=4.2X+3.2.2X
= 4.2X+6.2x
=2X.(4+6)
= 2X.10=80
2X=80:10
2X= 8
X= 8:2
X=4
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Lời giải:
$2^x+4.2^{x+1}+3.2^{x+2}=92$
$2^x+8.2^x+12.2^x=92$
$2^x(1+8+12)=92$
$2^x.21=92$
$2^x=\frac{92}{21}$ không là số tự nhiên. Đề có vẻ sai.
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\(d,3.2^{x+2}-9.2^x=96\\ 3.2^2.2^x-9.2^x=96\\ 12.2^x-2^x.9\\ 2^x.\left(12-9\right)=96\\ 2^x.3=96\\ 2^x=96:3\\ 2^x=32\\ 2^x=2^5\\ x=5\)
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a)7.2x=56⇔2x=8⇔2x=23⇔x=3
b)(2x+1)3=9.81⇔(2x+1)3=93⇔2x+1=9⇔2x=8⇔x=4
c)x3=82⇔x3=26⇔x=22⇔x=4
d)4.2x-3=1⇔4.2x=4⇔2x=1⇔2x=20⇔x=0
e)2.3x=162⇔3x=81⇔3x=34⇔x=4
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4.2x – 3 = 125
4.2x = 125 + 3
4.2x = 128
2x = 128 : 4
2x = 32
2x = 25
x = 5
Vậy x = 5
1/2.2x+4.2x=9.2x
2x.(1/2+4)=9.2x
2x.9/2=9.2x
2x:2x=9:9/2
x=2
vậy x=2