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{\(\frac{112}{200}\)+ 0,415} : 0,01
= {\(\frac{112}{200}+\frac{415}{1000}\)} : \(\frac{1}{100}\)
={\(\frac{560}{1000}\)+\(\frac{415}{1000}\)} : \(\frac{1}{100}\)
=\(\frac{975}{1000}\): \(\frac{1}{100}\)
=\(\frac{975}{1000}\)x\(\frac{100}{1}\)
=\(\frac{97500}{1000}\)=\(97,5\)
\(\frac{1}{2}-37,5+3-\frac{1}{6}\)
=\(\frac{1}{2}-\frac{375}{10}+\frac{3}{1}-\frac{1}{6}\)
=\(\frac{15}{30}-\frac{1125}{30}+\frac{90}{30}-\frac{5}{30}\)
=\(\frac{15-1125+90-5}{30}\)
=\(\frac{\left(-1110\right)+85}{30}\)
=\(\frac{-1025}{30}\)
Mik ko chắc!!!
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\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
=\(\frac{102}{-34}=-3\)
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a, \(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
= \(\dfrac{28}{15}.\dfrac{25}{100}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
= \(\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{32-79}{60}\right).\dfrac{24}{47}\)
= \(\dfrac{84}{60}+\dfrac{-47}{60}.\dfrac{24}{47}\)
= \(\dfrac{84}{60}+\dfrac{-24}{60}=\dfrac{60}{60}=1\)
b, \(\dfrac{\left(\dfrac{11^2}{200}+0,415\right):0,01}{\dfrac{1}{12}-37,25+3\dfrac{1}{6}}\)
= \(\dfrac{\left(\dfrac{121}{200}+\dfrac{415}{1000}\right):\dfrac{1}{100}}{\dfrac{1}{12}-\dfrac{3725}{100}+\dfrac{19}{6}}=\dfrac{\left(\dfrac{121}{200}+\dfrac{83}{200}\right).100}{\dfrac{1}{12}-\dfrac{149}{4}+\dfrac{19}{6}}\)
= \(\dfrac{\dfrac{51}{50}.100}{-34}=\dfrac{102}{-34}=-3\)