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\(2,\)
\(a,20-\left[4^2+\left(x-6\right)\right]=90\)
\(\Rightarrow20-16-x+6=90\)
\(\Rightarrow10-x=90\)
\(\Rightarrow x=-80\)
Vậy: \(x=-80\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2^x-6\right)\right]=3^2+4^2\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2^x-6\right)=25\)
\(\Rightarrow24+2^x=40\)
\(\Rightarrow2^x=16\)
\(\Rightarrow x=4\)
Vậy: \(x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2,\)
\(a,20-\left[42+\left(x-6\right)\right]=90\)
\(\Rightarrow20-42-x+6-90=0\)
\(\Rightarrow x=-106\)
Vậy: \(x=-106\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2x-6\right)\right]=32+42\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2x-6\right)=74\)
\(\Rightarrow1000:\left(24+2x\right)=74\)
\(\Rightarrow24+2x=\dfrac{500}{37}\)
\(\Rightarrow2x=-\dfrac{388}{37}\)
\(\Rightarrow x=-\dfrac{194}{37}\)
Mà \(x\in N\)
\(\Rightarrow x\in\varnothing\)
Vậy: \(x\in\varnothing\)
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\(1000:\text{[}30+\left(2^x-6\right)\text{]}=3^2+4^2\)
\(1000:\text{[}30+\left(2^x-6\right)\text{]}=9+16\)
\(1000:\text{[}30+\left(2^x-6\right)\text{]}=25\)
\(\text{ }30+\left(2^x-6\right)\text{ }=40\)
\(2^x-6=10\)
\(2^x=16\)
\(=>2^x=2^4\)
\(=>x=4\)
\(1000:\left[30+\left(2^x-6\right)\right]=3^2+4^2\\ 1000:\left[30+\left(2^x-6\right)\right]=9+16\\ 1000:\left[30+\left(2^x-6\right)\right]=25\\ 30+\left(2^x-6\right)=1000:25\\ 30+\left(2^x-6\right)=40\\ 2^x-6=40-30\\ 2^x-6=10\\ 2^x=10+6\\ 2^x=16\\ 2^x=2^4\\ x=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow42-2x-32+6=6\\ \Rightarrow16-2x=6\\ \Rightarrow2x=10\\ \Rightarrow x=5\)
\(\Rightarrow42-2x-32+6=6\\ \Rightarrow16-2x=6\\ \Rightarrow2x=10\\ \Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
42 - (2x + 32) + 12 = 6.2
42 - (2x + 32) + 12 = 12
42 - (2x + 32 ) = 12 - 12
42 - (2x + 32) = 0
2x + 32 = 42 - 0
2x + 32 = 42
2x = 42 - 32
2x = 10
=> x = 10 : 2
=> x = 5
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a)\(-x+\left(-53\right)=\left(-42\right)-41\Rightarrow-x+\left(-53\right)=\left(-83\right)\Rightarrow x=\left(-83\right)-\left(-53\right)=-30\)b) \(-12-x=-32+19\Rightarrow-12-x=-13\Rightarrow x=12--13=25\)c)\(453+x=-443+-199\Rightarrow453+x=-562\Rightarrow x=-562-453=-1015\)d)(đề trùng b mk ko làm nha)
e) \(32.\left(-2\right)+x=-120-5.\left(-85\right)\Rightarrow-64+x=545\Rightarrow x=545--64=609\)g)
\(-2x+15.\left(-4\right)=21.\left(-8\right)-12\Rightarrow-2x+-60=-180\Rightarrow2x=-120\Rightarrow x=-60\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( -2x - 28 )5 = -32 = ( -2 )5
-2x - 28 = -2
-2x = ( -2 ) + 28 = 26
x = 26 : ( -2 ) = -13
b) ( 7x - 11 )3 = 1000 = 103
7x - 11 = 10
7x = 10 + 11 = 21
x = 21 : 7 = 3
c) ( 3x - 15 )2 - 6 = 75
( 3x - 15 )2 = 75 + 6 = 81 = 92
3x - 15 = 9
3x = 9 + 15 = 24
x = 24 : 3 = 8
1000 : [30 + (2x - 6)] = 32 + 42
= 1000 : [ 30 + (2x-6)] = 9 + 16 = 25
= 30 + (2x - 6) = 1000 : 25 = 40
= 2x - 6 = 40 - 30 = 10
2x = 10 + 6 = 16
⇒ 2x = 24
⇒ x = 4
\(\Leftrightarrow2^x+24=40\)
hay x=4