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2021.1001 - 2021
= 2021.1001 - 2021. 1
= 2021. ( 1001 - 1 )
= 2021. 1000
= 2021000.
a: \(=2021\cdot\left(1001-1\right)=2021000\)
b: \(=135\cdot3^3+5\cdot3^3\cdot4-5\cdot3^4\)
\(=3^3\left(135+20\right)-5\cdot3^4\)
\(=3^3\cdot155-5\cdot3^4\)
\(=3^3\left(155-5\cdot3\right)=27\cdot140=3780\)
95 - (129 - 74) : 5 + 2022⁰
= 95 - 55 : 5 + 1
= 95 - 11 + 1
= 95 - 10
= 85
-------
(-67) + 125 + (-33) + 75
= (125 + 75) - (67 + 33)
= 200 - 100
= 100
--------
86.(-108) + 86.9 - 86
= 86.(-108 + 9 - 1)
= 86.(-100)
= 8600
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
a)
-37 +14 +26+37=(-37+37)+(14+26)=30
b) =(-24+24)+(6+10)=16
c)=(-23+23)+(25+15)=40
d)=(-33+33)+(-50+60)=10
e)=(-209+209)+[-14+(-16)]=-30
A=33. \(\left(1-\frac{2}{3}\right)\left(1-\frac{2}{5}\right)...\left(1-\frac{2}{99}\right)\)
A=33.\(\frac{1}{3}.\frac{3}{5}....\frac{97}{99}\)
A=33.\(\frac{1}{99}\)
A=\(\frac{33}{99}=\frac{1}{3}\)
1.202200
2.3780
\(2022\cdot99+2022=2022\left(99+1\right)=2022\cdot100=202200\)
\(135\cdot3^3+5\left(3^3\cdot4-3^4\right)\)
\(=135\cdot3^3+5\cdot3^3\cdot4-5\cdot3^4\)
\(=3^3\cdot\left(135+5\cdot4-5\cdot3\right)=3^3\cdot140=1260\)