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2,
a,Vì (2x+1) (3y-2)=12
\(\Rightarrow\left(2x+1;3y-2\right)\inƯ\left(12\right)=\left\{-1;1;-2;2;-3;3;-4;4;-6;6;-12;12\right\}\)
Lập bảng tự tính tiếp nhé............
Vậy ta lập được các cặp (x;y)là :(Tự tìm)
b,Làm tương tự a.
Nhớ nhấn đúng nha!
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a. \(5^{127}=5.5^{126}=5.125^{72}>119^{72}\)
\(\Rightarrow5^{217}>119^{72}\)
b. \(2^{1000}=\left(2^5\right)^{200}=32^{200}\)
\(5^{400}=\left(5^2\right)^{200}=25^{200}\)
\(\Rightarrow2^{1000}>5^{400}\)
c. \(9^{12}=\left(3^2\right)^{12}=3^{24}\)
\(27^7=\left(3^3\right)^7=3^{21}\)
\(\Rightarrow9^{12}>27^7\)
d. \(125^{80}=\left(5^3\right)^{80}=5^{240}\)
\(25^{118}=\left(5^2\right)^{118}=5^{236}\)
\(\Rightarrow125^{80}>25^{118}\)
e. \(5^{40}=\left(5^4\right)^{10}=625^{10}\)
\(\Rightarrow5^{40}>620^{10}\)
f. \(27^{11}=\left(3^3\right)^{11}=3^{33}\)
\(81^8=\left(3^4\right)^8=3^{32}\)
\(\Rightarrow27^{11}>81^8\)
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a ) 87 . ( − 2 0 ) < | 87 . ( − 2 0 ) |
b ) 87 . ( − 2 0 ) = 87 . ( − 2 0 )
c ) 87 . ( − 2 0 ) = − | − 87 . 2 0 |
![](https://rs.olm.vn/images/avt/0.png?1311)
(Sửa \(cn-bm\rightarrow cn-dm\))
Ta có :
\(\left\{{}\begin{matrix}ad-bc=1\\cn-dm=1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}ad=1+bc\\cn=1+dm\end{matrix}\right.\)
\(\dfrac{x}{y}=\dfrac{a}{b}.\dfrac{d}{c}=\dfrac{ad}{bc}=\dfrac{1+bc}{bc}=1+\dfrac{1}{bc}>1\left(bc>0\right)\)
\(\Rightarrow x=\dfrac{a}{b}>y=\dfrac{c}{d}\left(2\right)\)
\(\dfrac{y}{z}=\dfrac{c}{d}.\dfrac{n}{m}=\dfrac{cn}{dm}=\dfrac{1+dm}{dm}=1+\dfrac{1}{dm}>1\left(dc>0\right)\)
\(\Rightarrow y=\dfrac{c}{d}>z=\dfrac{m}{n}\left(2\right)\)
\(\left(1\right);\left(2\right)\Rightarrow x>y>z\)
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a)Vì x,y thuộc N => 2x+1,y-3 thuộc N =>2x+1 thuộc Ư(10)={-10;-5;-2;-1;1;2;5;10}
Lập bảng:
2x+1 | -10 | -5 | -2 | -1 | 1 | 2 | 5 | 10 |
y-3 | -1 | -2 | -5 | -10 | 10 | 5 | 2 | 1 |
x | -5.5 | -3 | -1.5 | -1 | 0 | 0.5 | 2 | 4.5 |
y | 2 | 1 | -2 | -7 | 13 | 8 | 5 | 4 |
KL | L | L | L | L | C | L | C | L |
Vậy (x;y)=(0;13);(2;5)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lộn, lộn,
\(3^{450}=\left(3^3\right)^{150}=27^{150}\)
Vì \(27^{150}>25^{150}\)nên \(A>B\)
1) Ta có: \(3^{450}=\left(3^3\right)^{150}=9^{150}\).
\(5^{300}=\left(5^2\right)^{150}=25^{150}\)
Ví \(9^{150}< 25^{150}\)nên \(3^{450}< 5^{300}\)
\(\Rightarrow A< B\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Sửa đề: B=11^87+1/11^88+1
\(11A=\dfrac{11^{90}+11}{11^{90}+1}=1+\dfrac{10}{11^{90}+1}\)
\(11B=\dfrac{11^{88}+11}{11^{88}+1}=1+\dfrac{10}{11^{88}+1}\)
mà 11^90>11^88
nên A<B
a) a>b vi 1234>999
b) x<y vi 8754<87540